大约有 37,000 项符合查询结果(耗时:0.0518秒) [XML]

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Calculating frames per second in a game

... 100 You need a smoothed average, the easiest way is to take the current answer (the time to draw th...
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Get exit code of a background process

... 130 1: In bash, $! holds the PID of the last background process that was executed. That will tell y...
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Count number of matches of a regex in Javascript

... | edited Apr 10 '18 at 20:52 Trevor 11.4k1111 gold badges6767 silver badges9090 bronze badges ...
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What is the difference between tinyint, smallint, mediumint, bigint and int in MySQL?

...------ tinyint | 1 byte -128 to 127 0 to 255 smallint | 2 bytes -32768 to 32767 0 to 65535 mediumint | 3 bytes -8388608 to 8388607 0 to 16777215 int/integer | 4 bytes -2147483648 to 2147483647 ...
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Difference between Big-O and Little-O Notation

... O(g) says, essentially For at least one choice of a constant k > 0, you can find a constant a such that the inequality 0 <= f(x) <= k g(x) holds for all x > a. Note that O(g) is the set of all functions for which this condition holds. f ∈ o(g) says, essentially For every c...
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How do I use valgrind to find memory leaks?

...a Valgrind report that looks like this: HEAP SUMMARY: in use at exit: 0 bytes in 0 blocks total heap usage: 636 allocs, 636 frees, 25,393 bytes allocated All heap blocks were freed -- no leaks are possible ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 0 from 0) ERROR SUMMARY: 0 error...
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What is a bank conflict? (Doing Cuda/OpenCL programming)

... 105 For nvidia (and amd for that matter) gpus the local memory is divided into memorybanks. Each ba...
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Return a value if no rows are found in Microsoft tSQL

...hat doesn't exist then I will get nothing returned. I'd prefer that false (0) is returned in that scenario. Looking for the simplest method to account for no records. ...
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How can I round down a number in Javascript?

... | edited Sep 30 '19 at 10:01 Gerrit Bertier 3,1071515 silver badges2727 bronze badges answer...
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Iterating over a numpy array

...>>> for (x,y), value in numpy.ndenumerate(a): ... print x,y ... 0 0 0 1 1 0 1 1 2 0 2 1 Regarding the performance. It is a bit slower than a list comprehension. X = np.zeros((100, 100, 100)) %timeit list([((i,j,k), X[i,j,k]) for i in range(X.shape[0]) for j in range(X.shape[1]) for k...