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How to print without newline or space?
I'd like to do it in python . What I'd like to do in this example in c :
22 Answers
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Convert python datetime to epoch with strftime
... you want to convert a python datetime to seconds since epoch you could do it explicitly:
>>> (datetime.datetime(2012,04,01,0,0) - datetime.datetime(1970,1,1)).total_seconds()
1333238400.0
In Python 3.3+ you can use timestamp() instead:
>>> datetime.datetime(2012,4,1,0,0).times...
How can I safely create a nested directory?
... is the most elegant way to check if the directory a file is going to be written to exists, and if not, create the directory using Python? Here is what I tried:
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Unique ways to use the Null Coalescing operator [closed]
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Well, first of all, it's much easier to chain than the standard ternary:
string anybody = parm1 ?? localDefault ?? globalDefault;
vs.
string anyboby = (parm1 != null) ? parm1
: ((localDefault != null) ? localDefault
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UnicodeDecodeError: 'ascii' codec can't decode byte 0xd1 in position 2: ordinal not in range(128)
I am attempting to work with a very large dataset that has some non-standard characters in it. I need to use unicode, as per the job specs, but I am baffled. (And quite possibly doing it all wrong.)
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Read String line by line
Given a string that isn't too long, what is the best way to read it line by line?
11 Answers
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Express: How to pass app-instance to routes from a different file?
I want to split up my routes into different files, where one file contains all routes and the other one the corresponding actions. I currently have a solution to achieve this, however I need to make the app-instance global to be able to access it in the actions.
My current setup looks like this:
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How can I ensure that a division of integers is always rounded up?
... blog in January 2013. Thanks for the great question!
Getting integer arithmetic correct is hard. As has been demonstrated amply thus far, the moment you try to do a "clever" trick, odds are good that you've made a mistake. And when a flaw is found, changing the code to fix the flaw without cons...
Check if element exists in jQuery [duplicate]
... me.
You need to put # before element id:
$('#elemId').length
---^
With vanilla JavaScript, you don't need the hash (#) e.g. document.getElementById('id_here') , however when using jQuery, you do need to put hash to target elements based on id just like CSS.
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Django 1.7 throws django.core.exceptions.AppRegistryNotReady: Models aren't loaded yet
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This is what solved it for us and these folks:
Our project started with Django 1.4, we went to 1.5 and then to 1.7. Our wsgi.py looked like this:
import os
from django.core.handlers.wsgi import WSGIHandler
os.environ['DJANGO_SETTINGS_MODULE'...
