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How to compare strings ignoring the case
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You're looking for casecmp. It returns 0 if two strings are equal, case-insensitively.
str1.casecmp(str2) == 0
"Apple".casecmp("APPLE") == 0
#=> true
Alternatively, you can convert both strings to lower case (str.downcase) and compare for equality.
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Hidden Features of JavaScript? [closed]
...function's arguments array-like object.
function sum() {
var retval = 0;
for (var i = 0, len = arguments.length; i < len; ++i) {
retval += arguments[i];
}
return retval;
}
sum(1, 2, 3) // returns 6
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Javascript and regex: split string and keep the separator
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106
Use (positive) lookahead so that the regular expression asserts that the special character exis...
Numpy index slice without losing dimension information
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It's probably easiest to do x[None, 10, :] or equivalently (but more readable) x[np.newaxis, 10, :].
As far as why it's not the default, personally, I find that constantly having arrays with singleton dimensions gets annoying very quickly. I'd guess the numpy...
Creating dataframe from a dictionary where entries have different lengths
Say I have a dictionary with 10 key-value pairs. Each entry holds a numpy array. However, the length of the array is not the same for all of them.
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Evenly distributing n points on a sphere
...orithm that can give me positions around a sphere for N points (less than 20, probably) that vaguely spreads them out. There's no need for "perfection", but I just need it so none of them are bunched together.
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A weighted version of random.choice
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Since version 1.7.0, NumPy has a choice function that supports probability distributions.
from numpy.random import choice
draw = choice(list_of_candidates, number_of_items_to_pick,
p=probability_distribution)
Note that probabi...
How do you get the width and height of a multi-dimensional array?
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answered Nov 23 '10 at 19:52
Reed CopseyReed Copsey
509k6868 gold badges10671067 silver badges13241324 bronze badges
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Return index of greatest value in an array
... works on old browsers:
function indexOfMax(arr) {
if (arr.length === 0) {
return -1;
}
var max = arr[0];
var maxIndex = 0;
for (var i = 1; i < arr.length; i++) {
if (arr[i] > max) {
maxIndex = i;
max = arr[i];
}
}
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MySQL IF NOT NULL, then display 1, else display 0
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Instead of COALESCE(a.addressid,0) AS addressexists, use CASE:
CASE WHEN a.addressid IS NOT NULL
THEN 1
ELSE 0
END AS addressexists
or the simpler:
(a.addressid IS NOT NULL) AS addressexists
This works because TRUE is displayed as 1 in ...