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What are the aspect ratios for all Android phone and tablet devices?
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║ 19.5 x 9 ║ 0.462... ║ 2.167... ║
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Matplotlib tight_layout() doesn't take into account figure suptitle
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Why #define TRUE (1==1) in a C boolean macro instead of simply as 1?
...) and actually use true and false.
In a C compiler, this is equivalent to 0 and 1.
(note that removing the parentheses will break that due to order of operations)
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How to put the legend out of the plot
I have a series of 20 plots (not subplots) to be made in a single figure. I want the legend to be outside of the box. At the same time, I do not want to change the axes, as the size of the figure gets reduced. Kindly help me for the following queries:
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String output: format or concat in C#?
...ded the result by some iterations was wrong. See what happens if you have 1000 milliseconds and 100 milliseconds. In both situations, you will get 0 ms after dividing it by 1000000.
Stopwatch s = new Stopwatch();
var p = new { FirstName = "Bill", LastName = "Gates" };
int n = 1000000;
long fElaps...
How do you get the width and height of a multi-dimensional array?
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answered Nov 23 '10 at 19:52
Reed CopseyReed Copsey
509k6868 gold badges10671067 silver badges13241324 bronze badges
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dyld: Library not loaded … Reason: Image not found
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@executable_path/libboost_something.dylib (compatibility version 0.7.0, current version 0.7.0)
/usr/lib/libc++.1.dylib (compatibility version 1.0.0, current version 65.1.0)
/usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 169.3.0)
and for each libb...
Change column type from string to float in Pandas
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+200
You have four main options for converting types in pandas:
to_numeric() - provides functionality to safely convert non-numeric types...
Why is there no xrange function in Python3?
...pple 2.7.2 64-bit:
In [37]: %timeit collections.deque((x for x in xrange(10000000) if x%4 == 0), maxlen=0)
1 loops, best of 3: 1.05 s per loop
Now, python.org 3.3.0 64-bit:
In [83]: %timeit collections.deque((x for x in range(10000000) if x%4 == 0), maxlen=0)
1 loops, best of 3: 1.32 s per loop
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How to compare strings ignoring the case
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You're looking for casecmp. It returns 0 if two strings are equal, case-insensitively.
str1.casecmp(str2) == 0
"Apple".casecmp("APPLE") == 0
#=> true
Alternatively, you can convert both strings to lower case (str.downcase) and compare for equality.
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