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Select statement to find duplicates on certain fields
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http://support.microsoft.com/kb/139444
There should be a criterion for deciding how you define "first rows" before you use the approach in the link above. Based on that you'll need to use an order by clause and a sub query if needed. If you can post some sample data, it would really help.
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Moving matplotlib legend outside of the axis makes it cutoff by the figure box
...out to Benjamin Root).
The code I am looking for is adjusting the savefig call to:
fig.savefig('samplefigure', bbox_extra_artists=(lgd,), bbox_inches='tight')
#Note that the bbox_extra_artists must be an iterable
This is apparently similar to calling tight_layout, but instead you allow savefig t...
Does application.yml support environment variables?
... @IgorDonin, would concatenation of variable assignments and program call an option for you? E. g.: $MY_ENV=value && java -jar ...
– PAX
May 12 at 12:31
add a co...
PHP Regex to get youtube video ID?
Can someone show me how to get the youtube id out of a url regardless of what other GET variables are in the URL.
19 Answer...
Alter a MySQL column to be AUTO_INCREMENT
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ALTER TABLE document MODIFY COLUMN document_id INT auto_increment
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How can I insert values into a table, using a subquery with more than one result?
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You want:
insert into prices (group, id, price)
select
7, articleId, 1.50
from article where name like 'ABC%';
where you just hardcode the constant fields.
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Converting Python dict to kwargs?
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and if you already have a dict object called "myDict" you just func(**myDict) .i.e myDict = {"type": "event"}
– James Khoury
Apr 19 '11 at 0:57
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jQuery - select the associated label element of a input field [duplicate]
...t. Just use the for attribute of the label, as it should correspond to the ID of the element you're currently manipulating:
var label = $("label[for='" + $(this).attr('id') + "']");
However, there are some cases where the label will not have for set, in which case the label will be the parent of ...
Django Reverse with arguments '()' and keyword arguments '{}' not found
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You have to specify project_id:
reverse('edit_project', kwargs={'project_id':4})
Doc here
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How to filter array in subdocument with MongoDB [duplicate]
...wind the list array before applying the $match so that you can filter individual elements and then use $group to put it back together:
db.test.aggregate([
{ $match: {_id: ObjectId("512e28984815cbfcb21646a7")}},
{ $unwind: '$list'},
{ $match: {'list.a': {$gt: 3}}},
{ $group: {_id:...