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Using the last-child selector
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last-child works in all the modern browsers, which means, of course, it does not work in any version of IE.
– Rob
Apr 8 '10 at 21:25
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Very Long If Statement in Python [duplicate]
...ther_long_identifier and
here_is_another_long_identifier != and_finally_another_long_name):
# ... your code here ...
pass
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Allowing Untrusted SSL Certificates with HttpClient
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Is there a way to do this without using all of your code? In other words, what is the gist of your solution?
– wensveen
Aug 21 '15 at 14:09
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What is the best way to create constants in Objective-C
...he file in the Reddit-Prefix.pch file to make the constants available to all the files. Is it a good way of doing things? Also, I've done my research and found several methods to create constants, but I don't know which one to use:
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jQuery get value of selected radio button
...use you when you're used to seeing "" as the default value via the .val() call.
– xji
Jan 8 '18 at 22:30
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Double decimal formatting in Java
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Optionally u might want to add another separator for digits more than 3 before the comma then use the following NumberFormat formatter = new DecimalFormat("#,000.00"); System.out.println(formatter.format(4.0));
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Immutable vs Mutable types
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Almost, but not exactly. Technically, all variables are passed by reference in Python, but have a semantics more like pass by value in C. A counterexample to your analogy is if you do def f(my_list): my_list = [1, 2, 3]. With pass-by-reference in C, the val...
“Unknown provider: aProvider
...that caused this issue, but I have since been able to find the problem manually.
There was a controller function declared on the global scope, instead of using a .controller() call on the application module.
So there was something like this:
function SomeController( $scope, i18n ) { /* ... */ }
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How can I manually generate a .pyc file from a .py file
...n not depend on Python's "import" statement to generate .pyc file automatically
8 Answers
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List of lists changes reflected across sublists unexpectedly
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When you write [x]*3 you get, essentially, the list [x, x, x]. That is, a list with 3 references to the same x. When you then modify this single x it is visible via all three references to it:
x = [1] * 4
l = [x] * 3
print(f"id(x): {id(x)}")
# id(x): 1405608979...