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Determine if two rectangles overlap each other?
...ram that takes the following inputs from the user to construct rectangles (between 2 and 5): height, width, x-pos, y-pos. All of these rectangles will exist parallel to the x and the y axis, that is all of their edges will have slopes of 0 or infinity.
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byte[] to hex string [duplicate]
How do I convert a byte[] to a string ? Every time I attempt it, I get
19 Answers
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What is the fastest or most elegant way to compute a set difference using Javascript arrays?
Let A and B be two sets. I'm looking for really fast or elegant ways to compute the set difference ( A - B or A \B , depending on your preference) between them. The two sets are stored and manipulated as Javascript arrays, as the title says.
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Python “extend” for a dictionary
What is the best way to extend a dictionary with another one while avoiding the use of a for loop? For instance:
7 Answer...
How can I select multiple columns from a subquery (in SQL Server) that should have one record (selec
I Know I can select a column from a subquery using this syntax:
5 Answers
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Simplest code for array intersection in javascript
What's the simplest, library-free code for implementing array intersections in javascript? I want to write
35 Answers
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How to concatenate two numbers in javascript?
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Use "" + 5 + 6 to force it to strings. This works with numerical variables too:
var a = 5;
var b = 6;
console.log("" + a + b);
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How to avoid overflow in expr. A * B - C * D
I need to compute an expression which looks like:
A*B - C*D , where their types are: signed long long int A, B, C, D;
Each number can be really big (not overflowing its type). While A*B could cause overflow, at same time expression A*B - C*D can be really small. How can I compute it correctly...
Sort array of objects by single key with date value
I have an array of objects with several key value pairs, and I need to sort them based on 'updated_at':
19 Answers
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How to check if two arrays are equal with JavaScript? [duplicate]
...ld do. Please do not use stringify nor < >.
function arraysEqual(a, b) {
if (a === b) return true;
if (a == null || b == null) return false;
if (a.length !== b.length) return false;
// If you don't care about the order of the elements inside
// the array, you should sort both array...