大约有 47,000 项符合查询结果（耗时：0.0635秒） [XML]
Get the current year in JavaScript
...ily: sans-serif;
}
<footer>
© <span id="year">2018</span> by FooBar
</footer>
share
|
improve this answer
|
follow
...
What does %~dp0 mean, and how does it work?
I find %~dp0 very useful, and I use it a lot to make my batch files more portable.
7 Answers
...
“x not in y” or “not x in y”
... 'ham' not in 'spam and eggs'
>>> dis.dis(notin)
2 0 LOAD_CONST 1 ('ham')
3 LOAD_CONST 2 ('spam and eggs')
6 COMPARE_OP 7 (not in)
9 POP_TOP
10 LOAD_CONST ...
Python unittests in Jenkins?
...il("shouldn't happen")
def test_pass(self):
self.assertEqual(10, 7 + 3)
def test_fail(self):
self.assertEqual(11, 7 + 3)
JUnit with pytest
run the tests with:
py.test --junitxml results.xml tests.py
results.xml:
<?xml version="1.0" encoding="utf-8"?>
<testsu...
.NET Global exception handler in console application
...|
edited May 29 '18 at 14:05
answered Jun 28 '10 at 14:32
H...
How to refresh app upon shaking the device?
... public void onSensorChanged(SensorEvent se) {
float x = se.values[0];
float y = se.values[1];
float z = se.values[2];
mAccelLast = mAccelCurrent;
mAccelCurrent = (float) Math.sqrt((double) (x*x + y*y + z*z));
float delta = mAccelCurrent - mAccelLast;
mAcc...
GetType() can lie?
...dFoo foo = new BadFoo();
Console.WriteLine("n1 and n2 are the same type: {0}",
Object.ReferenceEquals(n1.GetType(), foo.GetType()));
// output:
// n1 and n2 are the same type: True
so, yikes, you've successfully lied, right?
Well, yes and no... Consider that using this as an e...
What is the difference between “px”, “dip”, “dp” and “sp”?
...sed on the physical density of the screen. These units are relative to a 160
dpi screen, so one dp is one pixel on a 160 dpi screen. The ratio of
dp-to-pixel will change with the screen density, but not necessarily
in direct proportion. Note: The compiler accepts both "dip" and
...
Java 8 Stream and operation on arrays
... a = ...
int[] b = ...
int[] result = new int[a.length];
IntStream.range(0, a.length)
.forEach(i -> result[i] = a[i] * b[i]);
EDIT
Commenter @Holger points out you can use the map method instead of forEach like this:
int[] result = IntStream.range(0, a.length).map(i -> a[i] * b[...
How to get unique values in an array
...
120
Since I went on about it in the comments for @Rocket's answer, I may as well provide an example ...