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How to create a new branch from a tag?

...e to create a new master branch from an existing tag. Say I have a tag v1.0 . How to create a new branch from this tag? 7 ...
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How to easily resize/optimize an image size with iOS?

...one disk. Some of those images are pretty big in size (widths larger than 500 pixels, for instance). Since the iPhone doesn't even have a big enough display to show the image in its original size, I'm planning on resizing the image to something a bit smaller to save on space/performance. ...
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Get decimal portion of a number with JavaScript

... Use 1, not 2. js> 2.3 % 1 0.2999999999999998 share | improve this answer | follow | ...
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Math.random() versus Random.nextInt(int)

...tributed bits in its mantissa, so it is uniformly distributed in the range 0 to 1-(2^-53). Random.nextInt(n) uses Random.next() less than twice on average- it uses it once, and if the value obtained is above the highest multiple of n below MAX_INT it tries again, otherwise is returns the value ...
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How to split a sequence into two pieces by predicate?

...ing partition method: scala> List(1,2,3,4).partition(x => x % 2 == 0) res0: (List[Int], List[Int]) = (List(2, 4),List(1, 3)) share | improve this answer | follow ...
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DateTime to javascript date

... 10 Answers 10 Active ...
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How to get the first and last date of the current year?

Using SQL Server 2000, how can I get the first and last date of the current year? 18 Answers ...
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Converting a view to Bitmap without displaying it in Android?

...o. Its possible to measure it like this: if (v.getMeasuredHeight() <= 0) { v.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT); Bitmap b = Bitmap.createBitmap(v.getMeasuredWidth(), v.getMeasuredHeight(), Bitmap.Config.ARGB_8888); Canvas c = new Canvas(b); v.layout(0,...
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Combine two columns of text in pandas dataframe

I have a 20 x 4000 dataframe in Python using pandas. Two of these columns are named Year and quarter . I'd like to create a variable called period that makes Year = 2000 and quarter= q2 into 2000q2 . ...
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Removing a list of characters in string

...e) == test t = timeit.timeit(lambda: f(subj, chars_to_remove), number=1000) print ('{0:.3f} {1}'.format(t, f.__name__)) print (sys.version) PYTHON2 = sys.version_info[0] == 2 print ('\n"plain" string:\n') chars_to_remove = ['.', '!', '?'] subj = 'A.B!C?' * 1000 test = 'ABC' * 1000 profil...