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Best way to pretty print a hash
...\2:"). # "foo": 1 -> foo: 1
gsub(/(^\s*)(".*?"):/, "\\1\\2 =>") # "123": 1 -> "123" => 1
{
a: 1,
"2" => 3,
"3" => nil
}
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Python module os.chmod(file, 664) does not change the permission to rw-rw-r— but -w--wx----
Recently I am using Python module os, when I tried to change the permission of a file, I did not get the expected result. For example, I intended to change the permission to rw-rw-r--,
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How to identify whether a file is normal file or directory
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os.path.isdir() and os.path.isfile() should give you what you want. See:
http://docs.python.org/library/os.path.html
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How would you make a comma-separated string from a list of strings?
...gIO
import StringIO
import csv
l = ['list','of','["""crazy"quotes"and\'',123,'other things']
line = StringIO.StringIO()
writer = csv.writer(line)
writer.writerow(l)
csvcontent = line.getvalue()
# 'list,of,"[""""""crazy""quotes""and\'",123,other things\r\n'
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Which equals operator (== vs ===) should be used in JavaScript comparisons?
...n the third rule)
Now it becomes interesting:
var a = "12" + "3";
var b = "123";
alert(a === b); // returns true, because strings behave like value types
But how about this?:
var a = new String("123");
var b = "123";
alert(a === b); // returns false !! (but they are equal and of the same type)
I...
Get folder name from full file path
... answered Jun 27 '18 at 15:39
123iamking123iamking
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What does “xmlns” in XML mean?
...lt;homecity>
<name>London</name>
<lat>123.000</lat>
<long>0.00</long>
</homecity>
</person>
If our two XMLs were combined into a single document, how would we tell the two names apart? As you can see above, there are tw...
Get Android API level of phone currently running my application [duplicate]
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Check android.os.Build.VERSION, which is a static class that holds various pieces of information about the Android OS a system is running.
If you care about all versions possible (back to original Android version), as in minSdkVersion is ...
Get path of executable
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There is no cross platform way that I know.
For Linux: readlink /proc/self/exe
Windows: GetModuleFileName
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How to get the directory of the currently running file?
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This should do it:
import (
"fmt"
"log"
"os"
"path/filepath"
)
func main() {
dir, err := filepath.Abs(filepath.Dir(os.Args[0]))
if err != nil {
log.Fatal(err)
}
fmt.Println(dir)
}
...