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What is the difference between require and require-dev sections in composer.json?
...ts
The dependencies which are declared in the require section of composer.json are typically dependencies which are required for running an application or a package in
staging
production
environments, whereas the dependencies declared in the require-dev section are typically dependencies which...
Copy array by value
...oncat).
Array of literal-values (type1) and literal-structures (type2)
The JSON.parse(JSON.stringify(myArray)) technique can be used to deep copy literal values (boolean, number, string) and literal structures (array, object), but not prototype objects.
All arrays (type1, type2, type3)
The jQuery $....
How to get JSON objects value if its name contains dots?
I have a very simple JSON array (please focus on "points.bean.pointsBase" object):
5 Answers
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How to parse a JSON string to an array using Jackson
...ypeFactory();
List<SomeClass> someClassList = objectMapper.readValue(jsonString, typeFactory.constructCollectionType(List.class, SomeClass.class));
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No serializer found for class org.hibernate.proxy.pojo.javassist.Javassist?
I am working on SpringMVC , Hibernate & JSON but I am getting this error.
19 Answers
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.NET NewtonSoft JSON deserialize map to a different property name
I have following JSON string which is received from an external party.
5 Answers
5
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Convert JS Object to form data
... null ? '' : data;
formData.append(parentKey, value);
}
}
function jsonToFormData(data) {
const formData = new FormData();
buildFormData(formData, data);
return formData;
}
const my_data = {
num: 1,
falseBool: false,
trueBool: true,
empty: '',
und: undefined,
nullable: n...
How to inspect Javascript Objects
...That piece of code totally wrecked Safari Mobile on iPhone. I'd go for the JSON.stringify solution below for a safer alternative.
– Daniel
Aug 29 '12 at 9:35
1
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How to skip over an element in .map()?
...ources = images.filter(function(img) {
if (img.src.split('.').pop() === "json") {
return false; // skip
}
return true;
}).map(function(img) { return img.src; });
If you don't want to do that, which is not unreasonable since it has some cost, you can use the more general .reduce(). You can...
How to show full object in Chrome console?
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You might get better results if you try:
console.log(JSON.stringify(functor));
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