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Android: Specify two different images for togglebutton using XML
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edited Nov 13 '12 at 0:01
user901309
answered Oct 7 '09 at 18:37
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When is memoization automatic in GHC Haskell?
...situations. For example, consider the function
f = \x -> let y = [1..30000000] in foldl' (+) 0 (y ++ [x])
GHC might notice that y does not depend on x and rewrite the function to
f = let y = [1..30000000] in \x -> foldl' (+) 0 (y ++ [x])
In this case, the new version is much less effici...
Is it possible to display inline images from html in an Android TextView?
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Drawable d = getResources().getDrawable(id);
d.setBounds(0,0,d.getIntrinsicWidth(),d.getIntrinsicHeight());
return d;
}
};
You'd probably want to figure out something smarter for mapping source strings to resource IDs though.
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Android Studio needs JDK 7 for Android-L mac
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220
Setting the directory to:
/Library/Java/JavaVirtualMachines/jdk1.7.0_60.jdk/Contents/Home
in JDK...
Are loops really faster in reverse?
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907
It's not that i-- is faster than i++. Actually, they're both equally fast.
What takes time in ...
Check if a table exists in Rails
...ke task that won't work unless a table exists. I'm working with more than 20 engineers on a website so I want to make sure they have migrated the table before they can do a rake task which will populate that respective table.
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How can I add CGPoint objects to an NSArray the easy way?
I have about 50 CGPoint objects that describe something like a "path", and I want to add them to an NSArray. It's going to be a method that will just return the corresponding CGPoint for an given index. I don't want to create 50 variables like p1 = ...; p2 = ..., and so on. Is there an easy way that...
Updating MySQL primary key
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answered Feb 26 '10 at 14:20
MartinMartin
8,34455 gold badges3232 silver badges3333 bronze badges
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How to position one element relative to another with jQuery?
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204
NOTE: This requires jQuery UI (not just jQuery).
You can now use:
$("#my_div").position({
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Javascript Reduce an empty array
..., currentValue){
return Number(previousValue) + Number(currentValue);
}, 0);
or using ES6:
[].reduce( (previousValue, currentValue) => previousValue + currentValue, 0);
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