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What is the fastest or most elegant way to compute a set difference using Javascript arrays?
Let A and B be two sets. I'm looking for really fast or elegant ways to compute the set difference ( A - B or A \B , depending on your preference) between them. The two sets are stored and manipulated as Javascript arrays, as the title says.
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Access nested dictionary items via a list of keys?
...ataDict, mapList):
return reduce(operator.getitem, mapList, dataDict)
and reuse getFromDict to find the location to store the value for setInDict():
def setInDict(dataDict, mapList, value):
getFromDict(dataDict, mapList[:-1])[mapList[-1]] = value
All but the last element in mapList is need...
What is the difference between varchar and varchar2 in Oracle?
What is the difference between varchar and varchar2?
6 Answers
6
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Error: This Android SDK requires Android Developer Toolkit version 22.6.1 or above
...dt 20.x.x
Select the list items Let it be installed. Eclipse will restart and Its done.
I hope this will helpful for you :)
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Should it be “Arrange-Assert-Act-Assert”?
... need to ensure. Such a test should always fail if the precondition fails, and this means that I don't need it embedded in all the other tests. This gives a better isolation of concerns, since one test case only verifies one thing.
There may be many preconditions that need to be satisfied for a giv...
Differences between fork and exec
What are the differences between fork and exec ?
9 Answers
9
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How can I find the length of a number?
...34567;
x.toString().length;
This process will also work forFloat Number and for Exponential number also.
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AppStore - App status is ready for sale, but not in app store
... guess it messes up with the dates. Looks like sometimes if you do nothing and just follow the instructions, the app will never go live.
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How to create new tmux session if none exists
...session (start the server, read the config file, issue the new-session command) and attach to that.
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What is the easiest way to remove the first character from a string?
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p asdf
# >> "12,23,987,43"
I'm always looking for the fastest and most readable way of doing things:
require 'benchmark'
N = 1_000_000
puts RUBY_VERSION
STR = "[12,23,987,43"
Benchmark.bm(7) do |b|
b.report('[0]') { N.times { "[12,23,987,43"[0] = '' } }
b.report('sub') { N.time...