大约有 34,900 项符合查询结果（耗时：0.0358秒） [XML]
JavaScript data formatting/pretty printer
...p = result.replace(/, $/, "");
od.len = len;
return od;
}
I will look at improving it a bit.
Note 1: To use it, do od = DumpObject(something) and use od.dump. Convoluted because I wanted the len value too (number of items) for another purpose. It is trivial to make the function return only th...
How to get the current user in ASP.NET MVC
...ou specifically need in the ViewData, or you could just call User as I think it's a property of ViewPage.
share
|
improve this answer
|
follow
|
...
C++ sorting and keeping track of indexes
... answered Sep 13 '12 at 4:10
Łukasz WiklendtŁukasz Wiklendt
3,53022 gold badges1515 silver badges1515 bronze badges
...
Jump into interface implementation in Eclipse IDE
You know how in Eclipse, pressing F3 over a method will take you to its declaration? Well I have a method that is part of an interface; clicking F3 over this naturally takes me to the declaring interface.
...
How to sum up an array of integers in C#
...
Camilo Terevinto
24.5k66 gold badges5959 silver badges9292 bronze badges
answered Mar 10 '10 at 18:08
Tomas VanaTomas Vana...
How do I find files that do not contain a given string pattern?
...
ghostdog74ghostdog74
269k4848 gold badges233233 silver badges323323 bronze badges
...
Count number of rows within each group
I have a dataframe and I would like to count the number of rows within each group. I reguarly use the aggregate function to sum data as follows:
...
How to check if a variable is a dictionary in Python?
How would you check if a variable is a dictionary in python?
4 Answers
4
...
Is it possible to use pip to install a package from a private GitHub repository?
I am trying to install a Python package from a private GitHub repository. For a public repository, I can issue the following command which works fine:
...
How do I find the duplicates in a list and create another list with them?
...
To remove duplicates use set(a). To print duplicates, something like:
a = [1,2,3,2,1,5,6,5,5,5]
import collections
print([item for item, count in collections.Counter(a).items() if count > 1])
## [1, 2, 5]
Note that Counter is not particularly efficient (timings) and probably overkil...