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Using Spring MVC Test to unit test multipart POST request
...oader, but I am not managing to get it working. Nor do I manage to add the JSON part.
5 Answers
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Jackson databind enum case insensitive
How can I deserialize JSON string that contains enum values that are case insensitive? (using Jackson Databind)
13 Answers...
Ignoring new fields on JSON objects using Jackson [duplicate]
I'm using Jackson JSON library to convert some JSON objects to POJO classes on an android application. The problem is, the JSON objects might change and have new fields added while the application is published, but currently it will break even when a simple String field is added, which can safely be...
Convert objective-c typedef to its string equivalent
...tType {
NSString *result = nil;
switch(formatType) {
case JSON:
result = @"JSON";
break;
case XML:
result = @"XML";
break;
case Atom:
result = @"Atom";
break;
case RSS:
result...
Tool for generating railroad diagram used on json.org [closed]
I love the syntax of railroad diagrams on json.org which are a graphical representation of the BNF language. I haven't found any tools that can produce results as eloquently.
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failed to serialize the response in Web API
...ed answer did not work for me because it only changes the behaviour of the JSON formatter, but I was getting XML when I called the service from the browser.
To fix this, I switched off XML and forced only JSON to be returned.
In the Global.asax file, put the following lines at the top of your App...
How to escape a JSON string to have it in a URL?
.... The parameters to the page are in a Javascript array that I serialize in JSON.
6 Answers
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POST JSON to API using Rails and HTTParty
...
I solved this by adding .to_json and some heading information
@result = HTTParty.post(@urlstring_to_post.to_str,
:body => { :subject => 'This is the screen name',
:issue_type => 'Application Problem',
:stat...
How do I decode a string with escaped unicode?
...ent. For broader compatibility, use the below instead:
decodeURIComponent(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"'));
> 'http://example.com'
Original answer:
unescape(JSON.parse('"http\\u00253A\\u00252F\\u00252Fexample.com"'));
> 'http://example.com'
You can offload all...
How to change a field name in JSON using Jackson
I'm using jackson to convert an object of mine to json.
The object has 2 fields:
4 Answers
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