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Retrieving the output of subprocess.call() [duplicate]
...ut no means of accessing any of the streams. That's if using 2.6, if using 2.7 @Sergi answer could be used
– Willyfrog
Nov 12 '12 at 12:17
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Floating View 扩展：悬浮视图扩展，将组件转换为悬浮窗口 · App Inventor 2 中文网
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How to create a zip archive of a directory in Python?
...rchive of a directory structure in Python?
In a Python script
In Python 2.7+, shutil has a make_archive function.
from shutil import make_archive
make_archive(
'zipfile_name',
'zip', # the archive format - or tar, bztar, gztar
root_dir=None, # root for archive - current worki...
IRXmitter红外发射器扩展 · App Inventor 2 中文网
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Decode HTML entities in Python string?
... can use HTMLParser.unescape() from the standard library:
For Python 2.6-2.7 it's in HTMLParser
For Python 3 it's in html.parser
>>> try:
... # Python 2.6-2.7
... from HTMLParser import HTMLParser
... except ImportError:
... # Python 3
... from html.parser import HTMLPa...
How to efficiently compare two unordered lists (not sets) in Python?
...with sequences of unhashable objects as well.
New in version 3.2.
or in 2.7:
https://docs.python.org/2.7/library/unittest.html#unittest.TestCase.assertItemsEqual
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improve this answer
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Python dictionary: Get list of values for list of keys
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A little speed comparison:
Python 2.7.11 |Anaconda 2.4.1 (64-bit)| (default, Dec 7 2015, 14:10:42) [MSC v.1500 64 bit (AMD64)] on win32
In[1]: l = [0,1,2,3,2,3,1,2,0]
In[2]: m = {0:10, 1:11, 2:12, 3:13}
In[3]: %timeit [m[_] for _ in l] # list comprehension
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LEGO EV3 机器人按键控制 · App Inventor 2 中文网
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Check if a given key already exists in a dictionary
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Wanted to share that (using Python 2.7) the run time of something I just wrote, basing heavily on dicts, was 363.235070 using "key in dict.keys()" and drastically went down to 0.260186 solely by removing the call for "keys()"
– Ido_f
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“Cross origin requests are only supported for HTTP.” error when loading a local file
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In response to LukeP's comment, in python 2.7 the command does work as per the instructions $ python -m SimpleHTTPServer, which produces the message: Serving HTTP on 0.0.0.0 port 8000 ... If you spell the module name wrong, e.g. $ python -m SimpleHttpServer then you ...