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Get a random item from a JavaScript array [duplicate]
... not a valid substitution for Math.floor. Using round would cause accidentally referencing an undefined index, say in the case Math.random() is 0.95 and items.length is 5. Math.round(0.95*5) is 5, which would be an invalid index. floor(random) will always be zero in your example.
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What are Flask Blueprints, exactly?
...he string mold in Blueprint("mold", __name__)
– Codevalley
Aug 7 '17 at 6:48
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Django templates: verbose version of a choice
... (universal), though - unless you know a way to iterate in a template over all get_FOO_display methods of a model object :) I'm a bit too lazy for writing non-generic templates ;) Moreover, the docs say it's a model instance's method. Therefore it'd have to be a model form bound to an existing obj...
Check orientation on Android phone
...anging, because the launcher has locked the screen orientation and doesn't allow it to change. So it is correct that .orientation doesn't change, because the orientation hasn't changed. The screen is still portrait.
– hackbod
Feb 23 '12 at 8:32
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How do I get the directory that a program is running from?
... When I see code that looks at /proc part of me dies a little. All the world is not Linux, and even on that one platform /proc should be considered subject to change from version to version, arch to arch, etc.
– asveikau
Jan 28 '10 at 0:29
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Check if two unordered lists are equal [duplicate]
...has a built-in datatype for an unordered collection of (hashable) things, called a set. If you convert both lists to sets, the comparison will be unordered.
set(x) == set(y)
Documentation on set
EDIT: @mdwhatcott points out that you want to check for duplicates. set ignores these, so you need ...
Why does 'continue' behave like 'break' in a Foreach-Object?
...each that helps to make this conversion easy and make mistakes easy, too). All continues should be replaced with return.
P.S.: Unfortunately, it is not that easy to simulate break in ForEach-Object.
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Pythonic way to check if a list is sorted or not
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Actually we are not giving the answer anijhaw is looking for. Here is the one liner:
all(l[i] <= l[i+1] for i in xrange(len(l)-1))
For Python 3:
all(l[i] <= l[i+1] for i in range(len(l)-1))
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Check list of words in another string [duplicate]
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@Ockonal: and if you want to check that all words from that list are inside the string, just replace any() above with all()
– Nas Banov
Jul 17 '10 at 23:23
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Why does the MongoDB Java driver use a random number generator in a conditional?
...k && Math.random() <= 0.1)
return res;
The commit that originally introduced this logic had
if (_ok == true) {
_logger.log( Level.WARNING , "Server seen down: " + _addr, e );
} else if (Math.random() < 0.1) {
_logger.log( Level.WARNING , "Server seen down: " + _addr );
}
—a...