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Find if current time falls in a time range
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10 Answers
10
Active
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What are the best practices for JavaScript error handling?
...erprise JavaScript Error Handling can be found at http://www.devhands.com/2008/10/javascript-error-handling-and-general-best-practices/
In short it summarizes:
Assume your code will fail
Log errors to the server
You, not the browser, handle errors
Identify where errors might occur
Throw your own ...
How to open files relative to home directory
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109
The shell (bash, zsh, etc) is responsible for wildcard expansion, so in your first example the...
Create JSON object dynamically via JavaScript (Without concate strings)
...not need to count the rows with ´rowNum´?
– Xotic750
May 12 '13 at 12:45
1
push does not need r...
Read password from stdin
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answered Nov 19 '09 at 8:29
mjvmjv
65.3k1212 gold badges9595 silver badges146146 bronze badges
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How to find indices of all occurrences of one string in another in JavaScript?
...tive) {
var searchStrLen = searchStr.length;
if (searchStrLen == 0) {
return [];
}
var startIndex = 0, index, indices = [];
if (!caseSensitive) {
str = str.toLowerCase();
searchStr = searchStr.toLowerCase();
}
while ((index = str.indexOf(...
How to check if element has any children in Javascript?
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or the length property of childNodes:
if (element.childNodes.length > 0) { // Or just `if (element.childNodes.length)`
// It has at least one
}
If you only want to know about child elements (as opposed to text nodes, attribute nodes, etc.) on all modern browsers (and IE8 — in fact, eve...
Sorting dropdown alphabetically in AngularJS
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answered Sep 7 '12 at 3:02
GloopyGloopy
37.4k1515 gold badges9999 silver badges7171 bronze badges
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Ruby on Rails. How do I use the Active Record .build method in a :belongs to relationship?
...nd any documentation on the .build method in Rails (i am currently using 2.0.2).
2 Answers
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Find the most common element in a list
...# print 'SL:', SL
groups = itertools.groupby(SL, key=operator.itemgetter(0))
# auxiliary function to get "quality" for an item
def _auxfun(g):
item, iterable = g
count = 0
min_index = len(L)
for _, where in iterable:
count += 1
min_index = min(min_index, where)
...