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How can I pad an int with leading zeros when using cout
...) << 25;
}
the output will be
00025
setfill is set to the space character (' ') by default. setw sets the width of the field to be printed, and that's it.
If you are interested in knowing how the to format output streams in general, I wrote an answer for another question, hope it is us...
How to list files in a directory in a C program?
... function to print the content of a given folder */
void show_dir_content(char * path)
{
DIR * d = opendir(path); // open the path
if(d==NULL) return; // if was not able return
struct dirent * dir; // for the directory entries
while ((dir = readdir(d)) != NULL) // if we were able to read so...
warning: implicit declaration of function
...er has not seen the declaration. */
return 0;
}
int fun(int x, char *p)
{
/* ... */
}
You need to declare your function before main, like this, either directly or in a header:
int fun(int x, char *p);
sha...
Why doesn't Java support unsigned ints?
...
This is an older question and pat did briefly mention char, I just thought I should expand upon this for others who will look at this down the road. Let's take a closer look at the Java primitive types:
byte - 8-bit signed integer
short - 16-bit signed integer
int - 32-bit si...
Converting A String To Hexadecimal In Java
... {
return String.format("%040x", new BigInteger(1, arg.getBytes(/*YOUR_CHARSET?*/)));
}
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Exotic architectures the standards committees care about
...implementation-defined just because if there is an architecture with other characteristics, it would be very difficult or impossible to write a standard conforming compiler for it.
...
What does int argc, char *argv[] mean?
...ention, but they can be given any valid identifier: int main(int num_args, char** arg_strings) is equally valid.
They can also be omitted entirely, yielding int main(), if you do not intend to process command line arguments.
Try the following program:
#include <iostream>
int main(int argc,...
Converting String to “Character” array in Java
I want to convert a String to an array of objects of Character class but I am unable to perform the conversion. I know that I can convert a String to an array of primitive datatype type "char" with the toCharArray() method but it doesn't help in converting a String to an array of objects of C...
Unmangling the result of std::type_info::name
...clude <string>
#include <typeinfo>
std::string demangle(const char* name);
template <class T>
std::string type(const T& t) {
return demangle(typeid(t).name());
}
#endif
In file type.cpp (requires C++11)
#include "type.hpp"
#ifdef __GNUG__
#include <cstdlib>
#in...
Objective-C : BOOL vs bool
...mp; __LP64__) || TARGET_OS_WATCH
typedef bool BOOL;
#else
typedef signed char BOOL;
// BOOL is explicitly signed so @encode(BOOL) == "c" rather than "C"
// even if -funsigned-char is used.
#endif
#define YES ((BOOL)1)
#define NO ((BOOL)0)
So, yes, you can assume that BOOL is a char. You can ...