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string.Join on a List or other type
...le<T>)
If you can't upgrade, you can achieve the same effect using Select and ToArray.
return string.Join(",", a.Select(x => x.ToString()).ToArray());
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...
warning: implicit declaration of function
...er has not seen the declaration. */
return 0;
}
int fun(int x, char *p)
{
/* ... */
}
You need to declare your function before main, like this, either directly or in a header:
int fun(int x, char *p);
sha...
Why doesn't Java support unsigned ints?
...
This is an older question and pat did briefly mention char, I just thought I should expand upon this for others who will look at this down the road. Let's take a closer look at the Java primitive types:
byte - 8-bit signed integer
short - 16-bit signed integer
int - 32-bit si...
Exotic architectures the standards committees care about
...implementation-defined just because if there is an architecture with other characteristics, it would be very difficult or impossible to write a standard conforming compiler for it.
...
What does int argc, char *argv[] mean?
...ention, but they can be given any valid identifier: int main(int num_args, char** arg_strings) is equally valid.
They can also be omitted entirely, yielding int main(), if you do not intend to process command line arguments.
Try the following program:
#include <iostream>
int main(int argc,...
Entity Framework - Code First - Can't Store List
... Great solution for EF Core. Although it seems to have an issue whit char to string conversion. I had to implement it like such: .HasConversion( v => string.Join(";", v), v => v.Split(new char[] { ';' }, StringSplitOptions.RemoveEmptyEntries));...
Converting String to “Character” array in Java
I want to convert a String to an array of objects of Character class but I am unable to perform the conversion. I know that I can convert a String to an array of primitive datatype type "char" with the toCharArray() method but it doesn't help in converting a String to an array of objects of C...
Converting A String To Hexadecimal In Java
... {
return String.format("%040x", new BigInteger(1, arg.getBytes(/*YOUR_CHARSET?*/)));
}
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Objective-C : BOOL vs bool
...mp; __LP64__) || TARGET_OS_WATCH
typedef bool BOOL;
#else
typedef signed char BOOL;
// BOOL is explicitly signed so @encode(BOOL) == "c" rather than "C"
// even if -funsigned-char is used.
#endif
#define YES ((BOOL)1)
#define NO ((BOOL)0)
So, yes, you can assume that BOOL is a char. You can ...
Unmangling the result of std::type_info::name
...clude <string>
#include <typeinfo>
std::string demangle(const char* name);
template <class T>
std::string type(const T& t) {
return demangle(typeid(t).name());
}
#endif
In file type.cpp (requires C++11)
#include "type.hpp"
#ifdef __GNUG__
#include <cstdlib>
#in...