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How to avoid warning when introducing NAs by coercion

... answered Feb 20 '13 at 16:38 AndrieAndrie 157k3636 gold badges403403 silver badges464464 bronze badges ...
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What is the ellipsis (…) for in this method signature?

...id2, jid78_a, someOtherJid); See more here: http://java.sun.com/j2se/1.5.0/docs/guide/language/varargs.html share | improve this answer | follow | ...
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SQL SELECT WHERE field contains words

... mvpmvp 87.6k1111 gold badges100100 silver badges135135 bronze badges 3 ...
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What is Python buffer type for?

...' >>> t = buffer(s, 6, 5) >>> t <read-only buffer for 0x10064a4b0, size 5, offset 6 at 0x100634ab0> >>> print t world The buffer in this case is a sub-string, starting at position 6 with length 5, and it doesn't take extra storage space - it references a slice of t...
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Disable IntelliJ Starred (Package) Imports?

...ure can not be disabled. You need to set it to a high value, e.g. 99. In 2016.1.1 version You should also remove the lines under Packages to Use Import with '*', e.g. import javax.*; share | impro...
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How can I update my ADT in Eclipse?

... name. It will list the updates available- which should ideally be adt 20.xx Eclipse will restart and hopefully everything should work fine for you. share | improve this answer | ...
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Check whether a string matches a regex in JS

... regex.test() if all you want is a boolean result: console.log(/^([a-z0-9]{5,})$/.test('abc1')); // false console.log(/^([a-z0-9]{5,})$/.test('abc12')); // true console.log(/^([a-z0-9]{5,})$/.test('abc123')); // true ...and you could remove the () from your regexp since you've no n...
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Round a double to 2 decimal places [duplicate]

If the value is 200.3456 , it should be formatted to 200.34 . If it is 200 , then it should be 200.00 . 13 Answers ...
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Why is this program valid? I was trying to create a syntax error

...bar) to be written as new Foo $bar So that means Syntax error ! exit 0; is the same as error->Syntax(! exit 0); or error->Syntax(!exit(0)); Not only is it valid syntax, it doesn't result in a run-time error because the first thing executed is exit(0). ...
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Building C# Solution in Release mode using MSBuild.exe

...r solution(*.sln)] /t:Build /p:Configuration=Release /p:TargetFramework=v4.0 share | improve this answer | follow | ...