大约有 12,000 项符合查询结果（耗时：0.0226秒） [XML]
Find which version of package is installed with pip
...w Jinja2
---
Name: Jinja2
Version: 2.7.3
Location: /path/to/virtualenv/lib/python2.7/site-packages
Requires: markupsafe
In older versions, pip freeze and grep should do the job nicely.
$ pip freeze | grep Jinja2
Jinja2==2.7.3
...
What is the difference between `sorted(list)` vs `list.sort()`?
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In general, when a python function returns None, it is a sign, that the operations are done in place, that's why, when you want to print list.sort() it returns None.
– user1767754
Nov 19 '17 at 9:34
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How exactly does a generator comprehension work?
...ne question here. I used next(gen_name) to get the result and it worked in Python 3. Is there any specific scenario where we need to use __next__()?
– Ankit Vashistha
May 30 '18 at 6:12
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How do I activate a virtualenv inside PyCharm's terminal?
... has nothing to do with the OP's question. The problem is terminal not the Python interpreter. The venv integration has been there way before PyCharm 4. Your answer works though.
– Sam R.
Aug 3 '15 at 17:46
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tcp端口状态ESTABLISHED、TIME_WAIT、CLOSE_WAIT 、SYN_RECV等详解 - C/C++...
...接正确关闭
4、TIME_WAIT
我方主动调用close()断开连接，收到对方确认后状态变为TIME_WAIT。TCP协议规定TIME_WAIT状态会一直持续2MSL(即两倍的分 段最大生存期)，以此来确保旧的连接状态不会对新连接产生影响。处于TIME_WAIT状态的连...
Providing white space in a Swing GUI
...tzsch has a collection of presentations on UI design. In particular this PDF speaks to the need for aesthetic whitespace. Adding meaningful space while also paying attention to clutter separates the wheat from the chaff.
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How can I count the occurrences of a list item?
Given an item, how can I count its occurrences in a list in Python?
25 Answers
25
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how to return index of a sorted list? [duplicate]
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You can use the python sorting functions' key parameter to sort the index array instead.
>>> s = [2, 3, 1, 4, 5]
>>> sorted(range(len(s)), key=lambda k: s[k])
[2, 0, 1, 3, 4]
>>>
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Update value of a nested dictionary of varying depth
...t somewhat peculiar coding and at least one bug. I'd recommend, instead:
Python 2:
import collections
def update(d, u):
for k, v in u.iteritems():
if isinstance(v, collections.Mapping):
d[k] = update(d.get(k, {}), v)
else:
d[k] = v
return d
Pytho...
How to get item's position in a list?
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print(testlist.index(element) if element in testlist else None)
or the "pythonic way", which I don't like so much because code is less clear, but sometimes is more efficient,
try:
print testlist.index(element)
except ValueError:
pass
...