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Dynamic variable names in Bash
...[$1]}
}
If you can't use associative arrays (e.g., you must support bash 3), you can use declare to create dynamic variable names:
declare "magic_variable_$1=$(ls | tail -1)"
and use indirect parameter expansion to access the value.
var="magic_variable_$1"
echo "${!var}"
See BashFAQ: Indirec...
Should import statements always be at the top of a module?
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293
Module importing is quite fast, but not instant. This means that:
Putting the imports at the t...
Dealing with commas in a CSV file
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edited May 25 '14 at 23:21
Rory O'Kane
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How to split a string with any whitespace chars as delimiters
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the Tin Man
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answered Oct 22 '08 at 11:31
Henrik PaulHenr...
How to have the formatter wrap code with IntelliJ?
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edwardmlyte
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answered Oct 1 '10 at 9:38
Péter TörökPéte...
Find object in list that has attribute equal to some value (that meets any condition)
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Tropicalrambler
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answered Aug 19 '11 at 18:01
agfagf
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Assignment inside lambda expression in Python
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sqlalchemy: how to join several tables by one query?
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Ryabchenko Alexander
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answered May 18 '11 at 13:04
Abdul KaderAbdul ...
Replacing some characters in a string with another character
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340
echo "$string" | tr xyz _
would replace each occurrence of x, y, or z with _, giving A__BC__...
How to remove spaces from a string using JavaScript?
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edited Jul 10 '17 at 13:41
Jonathan
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answered ...
