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How do I revert master branch to a tag in git?
...ank']+1 }}: <stdin>:12706: trailing whitespace. error: patch failed: .env.wholo:1
– rickatech
Dec 19 '16 at 20:42
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Avoid web.config inheritance in child web application using inheritInChildApplications
...
I get this error "The configuration section 'configSections' cannot be read because it is missing a section declaration " in my parents web.config file.
– Blankman
Apr 23 '09 at 15:37
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jQuery post() with serialize and extra data
... },
success:function(data){
// json response
},
error: function(data) {
// if error occured
}
});
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f...
How to create a video from images with FFmpeg?
...format=yuv420p" "e:\out.mp4"
-safe 0 parameter prevents Unsafe file name error
Related links
FFmpeg making a video from images placed in different folders
FFMPEG An Intermediate Guide/image sequence
Concatenate – FFmpeg
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Determine installed PowerShell version
... shown launches Powershell using Command Prompt. Wouldn't the command just error out with "powershell not found" if it's not installed?
– jpmc26
Dec 12 '13 at 4:26
9
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Git is ignoring files that aren't in gitignore
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I had the same problem - a directory was being ignored by git with this error:
➭ git add app/views/admin/tags/
The following paths are ignored by one of your .gitignore files:
app/views/admin/tags
Use -f if you really want to add them.
fatal: no files added
I finally figured out my problem w...
What are the best PHP input sanitizing functions?
...erybody does it, and if you test what you do, you end up with a SQL syntax error with this omission. The real dangerous part is handled with mysql_real_escape_string.
– Savageman
Jun 27 '10 at 14:27
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Add a CSS class to
...> 'submit_class_name_here' %>
This should do. If you're getting an error, chances are that you're not supplying the name.
Alternatively, you can style the button without a class:
form#form_id_here input[type=submit]
Try that, as well.
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ViewModel Best Practices
...nt to POST from a partial view and return the whole view (in case of model error)? Within the partial view you don't have access to the parent model.
– Cosmo
Mar 15 '10 at 11:35
5
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JSON serialization of Google App Engine models
... output[key] = to_dict(value)
else:
raise ValueError('cannot encode ' + repr(prop))
return output
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