大约有 47,000 项符合查询结果（耗时：0.0428秒） [XML]
PHP code to convert a MySQL query to CSV [closed]
...;
(the documentation for this is here: http://dev.mysql.com/doc/refman/5.0/en/select.html)
or:
$select = "SELECT * FROM table_name";
$export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) );
$fields = mysql_num_fields ( $export );
for ( $i = 0; $i < $fields; $i++ )
{
...
shared_ptr to an array : should it be used?
...must be T[N] or T[]. So you may write
shared_ptr<int[]> sp(new int[10]);
From n4659, [util.smartptr.shared.const]
template<class Y> explicit shared_ptr(Y* p);
Requires: Y shall be a complete type. The expression delete[] p, when T is an array type, or delete p, when T is not...
Drop multiple tables in one shot in mysql
...
Leniel MaccaferriLeniel Maccaferri
91.3k4040 gold badges331331 silver badges445445 bronze badges
...
Serializing a list to JSON
...
If using .Net Core 3.0 or later;
Default to using the built in System.Text.Json parser implementation.
e.g.
using System.Text.Json;
var json = JsonSerializer.Serialize(aList);
alternatively, other, less mainstream options are available like...
Get cursor position (in characters) within a text Input field
...r) position of the specified text field (oField).
** Return value range is 0-oField.value.length.
*/
function doGetCaretPosition (oField) {
// Initialize
var iCaretPos = 0;
// IE Support
if (document.selection) {
// Set focus on the element
oField.focus();
// To get cursor po...
How do I find the last occurrence of a substring in an NSString?
...
answered Mar 13 '10 at 21:46
outisoutis
66.3k1717 gold badges125125 silver badges191191 bronze badges
...
Change a branch name in a Git repo
...
answered Oct 5 '10 at 19:25
Richard FearnRichard Fearn
22.6k55 gold badges5454 silver badges5353 bronze badges
...
Capturing Ctrl-c in ruby
...
answered Jan 18 '10 at 21:46
Wayne ConradWayne Conrad
85.6k1919 gold badges143143 silver badges180180 bronze badges
...
How to check if element has any children in Javascript?
...
or the length property of childNodes:
if (element.childNodes.length > 0) { // Or just `if (element.childNodes.length)`
// It has at least one
}
If you only want to know about child elements (as opposed to text nodes, attribute nodes, etc.) on all modern browsers (and IE8 — in fact, eve...
creating list of objects in Javascript
...
var list = [
{ date: '12/1/2011', reading: 3, id: 20055 },
{ date: '13/1/2011', reading: 5, id: 20053 },
{ date: '14/1/2011', reading: 6, id: 45652 }
];
and then access it:
alert(list[1].date);
...