大约有 970 项符合查询结果(耗时:0.0178秒) [XML]
Reading a resource file from within jar
...nk this should be works in java as well. The following code I use is using kotlin.
val resource = Thread.currentThread().contextClassLoader.getResource('resources.txt')
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Akka or Reactor [closed]
... are strongly committed to Groovy, people have already started Clojure and Kotlin ports. Add to this mix the fact that some requirements are driven by Spring XD and Grails.
Many thanks for your witnessed interest, hopefully you'll have more comparison points in a couple of months :)
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Setting background colour of Android layout element
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4 possible ways, use one you need.
1. Kotlin
val ll = findViewById<LinearLayout>(R.id.your_layout_id)
ll.setBackgroundColor(ContextCompat.getColor(this, R.color.white))
2. Data Binding
<LinearLayout
android:background="@{@color/white}"
OR more ...
How should I handle “No internet connection” with Retrofit on Android
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Replace Java with Kotlin if you're tired of NPEs and other syntax limitations/pain
– Louis CAD
Jun 25 '18 at 13:38
add...
外媒评本轮科技泡沫:创业公司首当其冲 九成将消失 - 资讯 - 清泛网 - 专注...
...元资产的银行,只要出现一个舍入误差,就可以购买大量编程人员以及位于旧金山黄金地段的办公地。
纳斯达克咨询服务机构科技行业分析师麦克·斯蒂勒(Mike Stiller)说,这种模式在投资者当中十分普遍。通常情况下,他都...
How to make part of the text Bold in android at runtime?
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You can do it using Kotlin and buildSpannedString extension function from core-ktx
holder.textView.text = buildSpannedString {
bold { append("$name\n") }
append("$experience $dateOfJoining")
}
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Multi-line EditText with Done action button
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To do this in Kotlin (and also optionally apply other configurations like textCapSentences you can use this extension function:
// To use this, do NOT set inputType on the EditText in the layout
fun EditText.setMultiLineCapSentencesAndDon...
Fragment over another fragment issue
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Kotlin version: root.setOnTouchListener { _, _ -> true}
– Gal Rom
Oct 29 '19 at 19:57
add a comme...
Regular expression to find URLs within a string
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Kotlin val urlRegex = "(?:(?:https?|ftp):\\/\\/)?[\\w/\\-?=%.]+\\.[\\w/\\-?=%.]+"
– Akshay Nandwana
Feb 27 '19 at 6:32
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What is the best way to tell if a character is a letter or number in Java without using regexes?
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On Kotlin it is much simpler if (c in 'a'..'z' || с in 'A'..'Z' || c in '0'..'9')
– Vlad
Jul 14 at 7:58
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