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Format in kotlin string templates
...ound, you can use something like:
"pi = ${pi.format(2)}"
the .format(n) function you'd need to define yourself as
fun Double.format(digits: Int) = "%.${digits}f".format(this)
There's clearly a piece of functionality here that is missing from Kotlin at the moment, we'll fix it.
...
What is the difference between “int” and “uint” / “long” and “ulong”?
...
This is quite fun to work out by hand. A 32-bit signed variable uses 1 bit for the sign (positive or negative) so can store values between -2^31 and +2^31 - 1
– Jaco Pretorius
Sep 16 '10 at 8:29
...
Javascript : natural sort of alphanumerical strings
...ebeckennebec
89.8k2828 gold badges9696 silver badges123123 bronze badges
...
C# DateTime to “YYYYMMDDHHMMSS” format
...e has great examples check it out
// create date time 2008-03-09 16:05:07.123
DateTime dt = new DateTime(2008, 3, 9, 16, 5, 7, 123);
String.Format("{0:y yy yyy yyyy}", dt); // "8 08 008 2008" year
String.Format("{0:M MM MMM MMMM}", dt); // "3 03 Mar March" month
String.Format("{0:d ...
AngularJS $resource RESTful example
...create a todo
var todo1 = new Todo();
todo1.foo = 'bar';
todo1.something = 123;
todo1.$save();
//get and update a todo
var todo2 = Todo.get({id: 123});
todo2.foo += '!';
todo2.$save();
//which is basically the same as...
Todo.get({id: 123}, function(todo) {
todo.foo += '!';
todo.$save();
});...
App Inventor 2 拓展参考文档 · App Inventor 2 中文网
...》。
【实用小技巧】从.aia项目文件中提取.aix拓展包
【自己写拓展】为AppInventor2开发拓展(Extension)
中文网拓展
【AI大模型】LLMAI2Ext 自研拓展：接入DeepSeek、Kimi、通义千问…等国内大模型，...
How do I do a bulk insert in mySQL using node.js
...wered Jan 10 '13 at 13:44
Ragnar123Ragnar123
4,12533 gold badges2020 silver badges3434 bronze badges
...
ImageView 扩展：图片查看器扩展，支持缩放、双击缩放和动画缩放 · App In...
...
下载链接
扩展文件：
com.dreamers.ImageViewer.aix
示例文件：
ImageView.aia
效果图：
功能概述
扩展特性
捏合缩放：支持双指捏合手势进行图片缩放
双击缩放：双击图片可进...
How to convert an Int to a String of a given length with leading zeros to align?
How can I convert an Int to a 7-character long String , so that 123 is turned into "0000123" ?
7 Answers
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Elements order in a “for (… in …)” loop
...[i,obj[i]].join(':'));
console.log(arr);
}
var obj = { a:1, b:2, c:3, "123":'xyz' };
/* log1 */ lineate(obj);
obj.a = 4;
/* log2 */ lineate(obj);
delete obj.a;
obj.a = 4;
/* log3 */ lineate(obj);
gist or test in current browser
Safari 5, Firefox 14
["a:1", "b:2", "c:3", "123:xyz"]
["a:4",...