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Why does flowing off the end of a non-void function without returning a value not produce a compiler
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C99 and C++ standards don't require functions to return a value. The missing return statement in a value-returning function will be defined (to return 0) only in the main function.
The rationale includes that checking if every code ...
Notifier 通知扩展：功能强大的Android通知管理工具，支持通知通道、意图、...
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Virtual functions and performance - C++
... functions (and more) is Member Function Pointers and the Fastest Possible C++ Delegates.
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DirectX SDK (June 2010) Installation Problems: Error Code S1023
...ers\\AppData\Local\Temp) for the most recent file named
Microsoft Visual C++ 2010 x64 Redistributable Setup_20110608_xxx.html ##
and check if you have the following error
Installation Blockers:
A newer version of Microsoft Visual C++ 2010 Redistributable has been detected on the machine...
Polymorphism in C++
...int and double), finding and executing distinct type-appropriate code.
C++ mechanisms for polymorphism
Explicit programmer-specified polymorphism
You can write f() such that it can operate on multiple types in any of the following ways:
Preprocessing:
#define f(X) ((X) += 2)
// (note: in re...
Why do you use typedef when declaring an enum in C++?
I haven't written any C++ in years and now I'm trying to get back into it. I then ran across this and thought about giving up:
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Setting an int to Infinity in C++
... That depends ont the implementation. There's no "Int64" in C++ (unless you count the stuff in C++11's cstdint).
– Etienne de Martel
Dec 31 '11 at 21:19
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Storing C++ template function definitions in a .CPP file
...ach you describe above.
I recommend reading the following points from the C++ FAQ Lite:
Why can’t I separate the definition of my templates class from its declaration and put it inside a .cpp file?
How can I avoid linker errors with my template functions?
How does the C++ keyword export help w...
What new capabilities do user-defined literals add to C++?
C++11 introduces user-defined literals which will allow the introduction of new literal syntax based on existing literals ( int , hex , string , float ) so that any type will be able to have a literal presentation.
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Why does the default parameterless constructor go away when you create one with parameters
In C#, C++ and Java, when you create a constructor taking parameters, the default parameterless one goes away. I have always just accepted this fact, but now I've started wondering why.
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