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What is the C# equivalent of friend? [duplicate]

...he private member variables of a class to be accessible to a Tester class without exposing them to other classes. 5 Answer...
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Last iteration of enhanced for loop in java

Is there a way to determine if the loop is iterating for the last time. My code looks something like this: 21 Answers ...
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Understanding REST: Verbs, error codes, and authentication

...an be helpful towards your RESTful venture. Point 1: Am I understanding it right? You understood right. That is a correct representation of a RESTful architecture. You may find the following matrix from Wikipedia very helpful in defining your nouns and verbs: When dealing with a Collection UR...
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In jQuery, how do I select an element by its name attribute?

... This should do it, all of this is in the documentation, which has a very similar example to this: $("input[type='radio'][name='theme']").click(function() { var value = $(this).val(); }); I should also note you have multiple identical...
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How to delete an item in a list if it exists?

I am getting new_tag from a form text field with self.response.get("new_tag") and selected_tags from checkbox fields with ...
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Resolving javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path

Edit :- Tried to format the question and accepted answer in more presentable way at mine Blog 22 Answers ...
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Is LINQ to SQL Dead or Alive?

Just when I make friends with LINQ to SQL, it appears as though MS is pulling the rug out from under it. 16 Answers ...
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Wrap long lines in Python [duplicate]

How do I wrap long lines in Python without sacrificing indentation? 6 Answers 6 ...
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How can I update NodeJS and NPM to the next versions?

I just installed Node.js and npm (for additional modules). 47 Answers 47 ...
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127 Return code from $?

... Value 127 is returned by /bin/sh when the given command is not found within your PATH system variable and it is not a built-in shell command. In other words, the system doesn't understand your command, because it doesn't know where to find the binary you're trying to call. ...