大约有 44,100 项符合查询结果(耗时:0.0412秒) [XML]

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How many double numbers are there between 0.0 and 1.0?

... Java doubles are in IEEE-754 format, therefore they have a 52-bit fraction; between any two adjacent powers of two (inclusive of one and exclusive of the next one), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that's the...
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Round to at most 2 decimal places (only if necessary)

I'd like to round at most 2 decimal places, but only if necessary . 79 Answers 79 ...
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How to check if all elements of a list matches a condition?

I have a list consisting of like 20000 lists. I use each list's 3rd element as a flag. I want to do some operations on this list as long as at least one element's flag is 0, it's like: ...
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What's the best practice to round a float to 2 decimals? [duplicate]

... I was working with statistics in Java 2 years ago and I still got the codes of a function that allows you to round a number to the number of decimals that you want. Now you need two, but maybe you would like to try with 3 to compare results, and this function giv...
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Rspec: “array.should == another_array” but without concern for order

... 265 Try array.should =~ another_array The best documentation on this I can find is the code itsel...
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counting number of directories in a specific directory

...* -maxdepth 0 -type d | wc -l 11 $ find .vim/ -maxdepth 1 -type d | wc -l 12 You can also use ls: $ ls -l .vim | grep -c ^d 11 $ ls -l .vim total 52 drwxrwxr-x 3 anossovp anossovp 4096 Aug 29 2012 after drwxrwxr-x 2 anossovp anossovp 4096 Aug 29 2012 autoload drwxrwxr-x 13 anossovp anossovp...
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Simple way to calculate median with MySQL

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How to filter object array based on attributes?

...p;& el.sqft >= 500 && el.num_of_beds >=2 && el.num_of_baths >= 2.5; }); Live Example: var obj = { 'homes': [{ "home_id": "1", "price": "925", "sqft": "1100", "num_of_beds": "2", ...
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How do I obtain the frequencies of each value in an FFT?

... where Fs is the sample rate and N is the size of the FFT. The next bin is 2 * Fs / N. To express this in general terms, the nth bin is n * Fs / N. So if your sample rate, Fs is say 44.1 kHz and your FFT size, N is 1024, then the FFT output bins are at: 0: 0 * 44100 / 1024 = 0.0 Hz 1: ...
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Replace values in list using Python [duplicate]

... 207 Build a new list with a list comprehension: new_items = [x if x % 2 else None for x in items]...