大约有 450 项符合查询结果（耗时：0.0184秒） [XML]
Regex to match a digit two or four times
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These will show the same result for either "333" and "33"
– Dan
Mar 1 '17 at 6:21
1
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How to construct a set out of list items in python?
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333
If you have a list of hashable objects (filenames would probably be strings, so they should co...
CSS hack大全 - 创意 - 清泛网 - 专注C/C++及内核技术
...owsers td{width:8%;text-align:center;padding:8px;}}
.browsercolor{color:#333;font-size:18px;font-weight:bold;}
.ie6{background-color:#1e0bd1}
.ie7{background-color:#a200ff}
.ie8{background-color:#00deff}
.firefox{background-color:#4eff00}
.opera{background-color:#4cac70}
.other{backgro...
Mean per group in a data.frame [duplicate]
...te(d[, 3:4], list(d$Name), mean)
Group.1 Rate1 Rate2
1 Aira 16.33333 47.00000
2 Ben 31.33333 50.33333
3 Cat 44.66667 54.00000
Here we aggregate columns 3 and 4 of data.frame d, grouping by d$Name, and applying the mean function.
Or, using a formula interface:
aggregate(. ~ ...
Grid of responsive squares
...__cell--4 {
flex-basis: 25%;
}
.square-grid__cell--3 {
flex-basis: 33.333%;
}
.square-grid__cell--2 {
flex-basis: 50%;
}
.square-grid__cell--1 {
flex-basis: 100%;
}
.square-grid {
display: flex;
flex-wrap: wrap;
justify-content: center;
}
.square-grid__cell {
backg...
Why does changing the sum order returns a different result?
...the nearest representable number. Here are two sums:
1/3 + 2/3 + 2/3 = (0.3333 + 0.6667) + 0.6667
= 1.000 + 0.6667 (no rounding needed!)
= 1.667 (where 1.6667 is rounded to 1.667)
2/3 + 2/3 + 1/3 = (0.6667 + 0.6667) + 0.3333
= 1.333 + 0.3333 (where 1...
Sticky sidebar: stick to bottom when scrolling down, top when scrolling up
...rent({
offset_top: 10
});
});
* {
font-size: 10px;
color: #333;
box-sizing: border-box;
}
.wrapper,
.header,
.main,
.footer {
padding: 10px;
position: relative;
}
.wrapper {
border: 1px solid #333;
background-color: #f5f5f5;
padding: 10px;
}
.header {
ba...
Way to get number of digits in an int?
...tem.out.println(i + " " + method1(i) + " " + method3(i));
for (int i = 333; i < 2000000000; i += 1000)
if (method1(i) != method3(i))
System.out.println(i + " " + method1(i) + " " + method3(i));
for (int i = 0; i < 1000; i++)
if (method1(i) != method4(i))
...
How Python web frameworks, WSGI and CGI fit together
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You can run WSGI over CGI as Pep333 demonstrates as an example. However every time there is a request a new Python interpreter is started and the whole context (database connections, etc.) needs to be build which all take time.
The best if you want to run ...
Amend a commit that wasn't the previous commit [duplicate]
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user3351225
333 bronze badges
answered Oct 13 '10 at 18:33
DaenythDaenyth
29.6k1010 gold b...