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Performant Entity Serialization: BSON vs MessagePack (vs JSON)
Recently I've found MessagePack , an alternative binary serialization format to Google's Protocol Buffers and JSON which also outperforms both.
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When should I use Arrow functions in ECMAScript 6?
The question is directed at people who have thought about code style in the context of the upcoming ECMAScript 6 (Harmony) and who have already worked with the language.
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Which letter of the English alphabet takes up most pixels?
I am trying to do some dynamic programming based on the number of characters in a sentence. Which letter of the English alphabet takes up the most pixels on the screen?
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php check if array contains all array values from another array
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Chris
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answered Mar 11 '12 at 14:21
jasonbarjasonbar
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Why declare unicode by string in python?
I'm still learning python and I have a doubt:
5 Answers
5
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Google Authenticator implementation in Python
I am trying to use one-time passwords that can be generated using Google Authenticator application .
2 Answers
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How to access the ith column of a NumPy multidimensional array?
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>>> test[:,0]
array([1, 3, 5])
Similarly,
>>> test[1,:]
array([3, 4])
lets you access rows. This is covered in Section 1.4 (Indexing) of the NumPy reference. This is quick, at least in my experience. ...
git diff between cloned and original remote repository
I have cloned a github repository and made no changes locally. Github repository moved forward with commits on the same branch.
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ManyRelatedManager object is not iterable
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Try
matches = [val for val in Store.attribute_answers.all() if val in WishList.attribute_answers.all()]
Notice the parenthesis at the end of WishList.attribute_answers.all(). Adding the parenthesis invokes the all function to return an iterable.
If you include t...
Python speed testing - Time Difference - milliseconds
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datetime.timedelta is just the difference between two datetimes ... so it's like a period of time, in days / seconds / microseconds
>>> import datetime
>>> a = datetime.datetime.now()
>>> b = datetime.datetime.now()
>>> c = b - a
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