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Python matplotlib multiple bars
...lotlib.dates import date2num
import datetime
x = [
datetime.datetime(2011, 1, 4, 0, 0),
datetime.datetime(2011, 1, 5, 0, 0),
datetime.datetime(2011, 1, 6, 0, 0)
]
x = date2num(x)
y = [4, 9, 2]
z = [1, 2, 3]
k = [11, 12, 13]
ax = plt.subplot(111)
ax.bar(x-0.2, y, width=0.2, color='b', ...
How to install a previous exact version of a NPM package?
I used nvm to download node v0.4.10 and installed npm to work with that version of node.
10 Answers
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What's the fastest way to convert String to Number in JavaScript?
...
There are 4 ways to do it as far as I know.
Number(x);
parseInt(x, 10);
parseFloat(x);
+x;
By this quick test I made, it actually depends on browsers.
http://jsperf.com/best-of-string-to-number-conversion/2
Implicit marked the fastest on 3 browsers, but it makes the code hard to read… S...
How do I reverse a C++ vector?
...{
std::vector<int> a;
std::reverse(a.begin(), a.end());
return 0;
}
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How do I make a transparent canvas in html5?
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edited Apr 16 '14 at 1:20
Lee Taylor
5,93777 gold badges2626 silver badges4343 bronze badges
answered ...
How can I get a count of the total number of digits in a number?
...
Without converting to a string you could try:
Math.Ceiling(Math.Log10(n));
Correction following ysap's comment:
Math.Floor(Math.Log10(n) + 1);
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How can I String.Format a TimeSpan object with a custom format in .NET?
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Please note: this answer is for .Net 4.0 and above. If you want to format a TimeSpan in .Net 3....
Swift - How to convert String to Double
...e: The NSString doubleValue property is not recommended because it returns 0 if the value cannot be converted (i.e.: bad user input).
let lessPrecisePI = Float("3.14")
let morePrecisePI = Double("3.1415926536")
let invalidNumber = Float("alphabet") // nil, not a valid number
Unwrap the values to...
Convert a number range to another range, maintaining ratio
...) + NewMin
Or if you want to protect for the case where the old range is 0 (OldMin = OldMax):
OldRange = (OldMax - OldMin)
if (OldRange == 0)
NewValue = NewMin
else
{
NewRange = (NewMax - NewMin)
NewValue = (((OldValue - OldMin) * NewRange) / OldRange) + NewMin
}
Note that in this...