大约有 37,000 项符合查询结果（耗时：0.0705秒） [XML]
[] and {} vs list() and dict(), which is better?
...s/dicts:
>>> from timeit import timeit
>>> timeit("[]")
0.040084982867934334
>>> timeit("list()")
0.17704233359267718
>>> timeit("{}")
0.033620194745424214
>>> timeit("dict()")
0.1821558326547077
and for non-empty:
>>> timeit("[1,2,3]")
0.243...
Can I change the viewport meta tag in mobile safari on the fly?
...]");
viewport.setAttribute('content', 'width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=0');
Just change the parts you need and Mobile Safari will respect the new settings.
Update:
If you don't already have the meta viewport tag in the source, you can append it directly wi...
What does tilde-greater-than (~>) mean in Ruby gem dependencies? [duplicate]
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207
It means "equal to or greater than in the last digit", so e.g. ~> 2.3 means
"equal to 2.3 or...
MFC窗口设置TopMost置顶的几种方法 - C/C++ - 清泛网 - 专注C/C++及内核技术
...种方法方法一：网上常见的pDlg->SetWindowPos(&CWnd::wndTopMost,0,0,0,0,SWP_NOMOVE|SWP_NOSIZE);或pDlg->SetWindowPos(pDlg->GetStyle() & WS...方法一：网上常见的
pDlg->SetWindowPos(&CWnd::wndTopMost, 0, 0, 0, 0, SWP_NOMOVE | SWP_NOSIZE); 或
pDlg->SetWindowPos(pDlg->GetStyle() & W...
JS文字卷动效果的调用函数：startmarquee - 更多技术 - 清泛网 - 专注C/C++及内核技术
...false直接影响到下面start()函数的执行；
o.scrollTop = 0;
//文字内容顶端与滚动区域顶端的距离，初始值为0；
function start(){
t=setInterval(scrolling,speed); //每隔一段时间，setInterval便会执行一次scrolling函数；speed...
ReactJS: Modeling Bi-Directional Infinite Scrolling
...render them, it's really cheap to just allocate them and discard them. If 10k allocations is too big, you can instead pass a function that takes a range and return the elements.
<List>
{thousandelements.map(function() { return <Element /> })}
</List>
Your List component is kee...
How to initialize all members of an array to the same value?
...
Unless that value is 0 (in which case you can omit some part of the initializer
and the corresponding elements will be initialized to 0), there's no easy way.
Don't overlook the obvious solution, though:
int myArray[10] = { 5, 5, 5, 5, 5, 5, 5,...
Python: Append item to list N times
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For immutable data types:
l = [0] * 100
# [0, 0, 0, 0, 0, ...]
l = ['foo'] * 100
# ['foo', 'foo', 'foo', 'foo', ...]
For values that are stored by reference and you may wish to modify later (like sub-lists, or dicts):
l = [{} for x in range(100)]
(Th...