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jquery loop on Json data using $.each

I have the following JSON returned in a variable called data. 4 Answers 4 ...
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Is there a way to 'pretty' print MongoDB shell output to a file?

...ifically, I want to print the results of a mongodb find() to a file. The JSON object is too large so I'm unable to view the entire object with the shell window size. ...
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convert ArrayList to JSONArray

...or a ListView. I need to take the items in the list and convert them to a JSONArray to send to an API. I've searched around, but haven't found anything that explains how this might work, any help would be appreciated. ...
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What is the JavaScript equivalent of var_dump or print_r in PHP? [duplicate]

... Most common way: console.log(object); However I must mention JSON.stringify which is useful to dump variables in non-browser scripts: console.log( JSON.stringify(object) ); The JSON.stringify function also supports built-in prettification as pointed out by Simon Zyx. Example: var ...
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Why is JsonRequestBehavior needed?

Why is Json Request Behavior needed? 5 Answers 5 ...
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Javascript: get package.json data in gulpfile.js

...gulp-specific question per-se, but how would one get info from the package.json file within the gulpfile.js; For instance, I want to get the homepage or the name and use it in a task. ...
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JSON parsing using Gson for Java

I would like to parse data from JSON which is of type String . I am using Google Gson . 11 Answers ...
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How to create index on JSON field in Postgres?

In PostgreSQL 9.3 Beta 2 (?), how do I create an index on a JSON field? I tried it using the -> operator used for hstore but got the following error: ...
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Ignore fields from Java object dynamically while sending as JSON from Spring MVC

... Add the @JsonIgnoreProperties("fieldname") annotation to your POJO. Or you can use @JsonIgnore before the name of the field you want to ignore while deserializing JSON. Example: @JsonIgnore @JsonProperty(value = "user_password") pu...
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Ajax success event not working

... The result is probably not in JSON format, so when jQuery tries to parse it as such, it fails. You can catch the error with error: callback function. You don't seem to need JSON in that function anyways, so you can also take out the dataType: 'json' row....