大约有 13,600 项符合查询结果（耗时：0.0248秒） [XML]
How can I generate a self-signed certificate with SubjectAltName using OpenSSL? [closed]
...ilAddress=test@example.com
Validity
Not Before: Feb 1 05:23:05 2014 GMT
Not After : Feb 1 05:23:05 2016 GMT
Subject: C=US, ST=MD, L=Baltimore, O=Test CA, Limited, CN=Test CA/emailAddress=test@example.com
Subject Public Key Info:
Public Ke...
Entity Framework 4 / POCO - Where to start? [closed]
...dvantages of a POCO approach.
http://blogs.msdn.com/b/adonet/archive/2009/05/21/poco-in-the-entity-framework-part-1-the-experience.aspx
http://blogs.msdn.com/b/adonet/archive/2009/05/28/poco-in-the-entity-framework-part-2-complex-types-deferred-loading-and-explicit-loading.aspx
http://blogs.msdn....
How to update npm
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edited Jun 28 '14 at 0:05
Daniel Imms
40.5k1313 gold badges123123 silver badges149149 bronze badges
a...
In Python, using argparse, allow only positive integers
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answered Jan 2 '13 at 6:05
aneroidaneroid
8,81522 gold badges3232 silver badges4949 bronze badges
...
Find objects between two dates MongoDB
... $gte: ISODate("2010-04-29T00:00:00.000Z"),
$lt: ISODate("2010-05-01T00:00:00.000Z")
}
})
=> { "_id" : ObjectId("4c0791e2b9ec877893f3363b"), "name" : "example", "created_at" : "Sun May 30 2010 00:00:00 GMT+0300 (EEST)" }
Based on my experiments you will need to serialize your da...
How to keep the spaces at the end and/or at the beginning of a String?
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answered Feb 5 '10 at 11:05
duessiduessi
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How do I do a Date comparison in Javascript? [duplicate]
...
new Date('1945/05/09').valueOf() < new Date('2011/05/09').valueOf()
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Watch multiple $scope attributes
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edited Mar 15 '14 at 13:05
answered Jun 20 '13 at 22:25
R...
Convert Python dict into a dataframe
...2-06-10': 388,
u'2012-06-11': 389,
u'2012-06-12': 389,
.....
u'2012-07-05': 392,
u'2012-07-06': 392}, orient='index', columns=['foo'])
Out[7]:
foo
2012-06-08 388
2012-06-09 388
2012-06-10 388
2012-06-11 389
2012-06-12 389
........
2012-07-05 392
2012-07-06 392
...
How to convert a factor to integer\numeric without loss of information?
...q max neval
## as.numeric(levels(f))[f] 3.982 5.120 6.088624 5.405 5.974 1981.418 1e+05
## as.numeric(levels(f)[f]) 5.973 7.111 8.352032 7.396 8.250 4256.380 1e+05
## as.numeric(as.character(f)) 6.827 8.249 9.628264 8.534 9.671 1983.694 1e+05
## paste0(x) 7....