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Swift 和 .Net 开源，回顾 2015 年 9 大开源事件 - 开源 & Github - 清泛网 - 专注IT技能提升
...布一个基于 MIT 开源许可的包括开源的效果，工具，库和SDK的套件。这个举措可以让开发者更好使用 AMD 的 GPU 资源，它被看做 Nvidia 的 Gameworks的开源替代品。
6、Google 开放人工智能资源
Google 不是第一次开源了，它早已因开源...
VS 2015 Preview版已经发布，支持Android开发 - IT产品资讯 - 清泛网 - 专注IT技能提升
...架，支持为Android 及未来的iOS开发应用。使用 Google Android SDK的开发者都知道，Google的Android 模拟器非常慢，微软开发了自己的Android模拟器，使用体验要好得多，它最终将能独立工作，其它集成开发环境如Eclipse可以使用微软的 Andr...
What is the Auto-Alignment Shortcut Key in Eclipse?
... "CTRL + ALT + L (Win)" as the answer out there.... developer.android.com/sdk/installing/…
– gumuruh
May 29 '14 at 5:13
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How can I change the image of an ImageView? [duplicate]
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if (android.os.Build.VERSION.SDK_INT >= 21) {
storeViewHolder.storeNameTextView.setImageDrawable(context.getResources().getDrawable(array[position], context.getTheme()));
} else {
storeViewHolder.storeNameTextView.setImageDrawa...
How to always show scrollbar
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available in sdk 16 as a java method
– larham1
Jun 12 '13 at 22:20
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Remove ListView separator(in the xml layout file) [duplicate]
...to remove divider
(not 0, 0.0, @null or the same in code)
Android Studio, SDK L, android 4.2
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UIWebView background is set to Clear Color, but it is not transparent
I'm developing an iOS 4 application using iOS SDK latest version and XCode 4.2.
8 Answers
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Exported service does not require permission: what does it mean?
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I had the same issue when I updated SDK to version 20. I removed it adding android:exported property android:exported="false" like so:
<service android:name=".MyService"
android:exported="false">
<intent-filter>
<action android:...
How to change the icon of an Android app in Eclipse?
I am developing an app using Eclipse IDE Juno and Android SDK.
6 Answers
6
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What do {curly braces} around javascript variable name mean [duplicate]
...ine.) Roughly, it would translate into this:
var ActionButton = require("sdk/ui/button/action").ActionButton;
It seems silly in this example, as there's only one item being assigned. However, you'd be able to use this pattern to assign multiple variables at once:
{x, y} = foo;
Is the equival...