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How can I clone an SQL Server database on the same server in SQL Server 2008 Express?
...> Task -> Backup).
Create empty database with new name (clone). Note comments below as this is optional.
Click to clone database and open restore dialog (see image)
Select Device and add the backup file from step 3.
Change destination to test database
Change location of database files, it ...
Why is \r a newline for Vim?
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From http://vim.wikia.com/wiki/Search_and_replace :
When Searching
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\n is newline, \r is CR (carriage return = Ctrl-M = ^M)
When Replacing
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\r is newline, \n is a null byte (0x00).
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remove None value from a list without removing the 0 value
... - it's just for scientific purposes)
>>> from operator import is_not
>>> from functools import partial
>>> L = [0, 23, 234, 89, None, 0, 35, 9]
>>> filter(partial(is_not, None), L)
[0, 23, 234, 89, 0, 35, 9]
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[精华]VC++对话框程序打印及打印预览的实现 - C/C++ - 清泛网 - 专注C/C++及内核技术
...程序文件菜单中会生成两个菜单项分别是打印（标识符ID_FILE_PRINT）和打印预览(标识符：ID_FILE_PRINT_PREVIEW)，展开程序源代码，可以发现，是CVIEW类提供标准打印和打印预览菜单命令的消息处理函数：
设应用程序视图类为CMyView,展...
How do I use JDK 7 on Mac OSX?
I would like to use the WatchService API as mentioned in this link:
http://download.oracle.com/javase/tutorial/essential/io/notification.html
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Objective-C: Property / instance variable in category
... So if you wanted to use this on multiple instances and have each instance compute a distinct value, it wouldn't work.
Fortunately, the Objective-C runtime has this thing called Associated Objects that can do exactly what you're wanting:
#import <objc/runtime.h>
static void *MyClassResultKe...
Advances social tools app with cool UI - Koded Apps - Kodular Community
... });
}
Kodular Community
Advances social tools app with cool UI
Koded Apps
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error LNK2019: 无法解析的外部符号_socket，该符号在函数 中被引用 - C/C+...
error LNK2019: 无法解析的外部符号_socket，该符号在函数 中被引用1>NetClient.obj : error LNK2019: 无法解析的外部符号 _closesocket@4，该符号在函数 _main 中被引用1>NetClient.obj : error L...1>NetClient.obj : error LNK2019: 无法解析的外部符号 _closesocket@...
ASP.NET MVC: Custom Validation by DataAnnotation
...ngth annotation. However I want to validate the length of the 4 properties combined.
6 Answers
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What is the most efficient way of finding all the factors of a number in Python?
...om functools import reduce
def factors(n):
return set(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
This will return all of the factors, very quickly, of a number n.
Why square root as the upper limit?
sqrt(x) * sqrt(x) = x. So if t...