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Fastest way to check if string contains only digits
...; int r = 12345678*2; var ss = new SortedSet<string>(); //s = string.Concat(Enumerable.Range(0, 127).Select(i => ((char)i ^ '0') < 10 ? 1 : 0));
w.Restart(); for (int i = 0; i < r; i++) b = s.All(char.IsDigit); w.Stop(); ss.Add(w.Elapsed + ".All .IsDigit");
w.Restart(); for (...
Ignoring accented letters in string comparison
...e function:
static string RemoveDiacritics(string text)
{
return string.Concat(
text.Normalize(NormalizationForm.FormD)
.Where(ch => CharUnicodeInfo.GetUnicodeCategory(ch)!=
UnicodeCategory.NonSpacingMark)
).Normalize(NormalizationForm.FormC...
Why is using the JavaScript eval function a bad idea?
...name to: badHackerGuy'); doMaliciousThings(); and if you take my username, concat it into some script and eval it in other people's browsers then I can run any javascript I want on their machines (e.g. force them to +1 my posts, post their data to my server, etc.)
– Prestaul
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Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array
... i, arr) => arr.indexOf(v) !== i && acc.indexOf(v) === -1 ? acc.concat(v) : acc, [])
– ZephDavies
Nov 29 '18 at 14:56
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Combine two columns of text in pandas dataframe
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if both columns are strings, you can concatenate them directly:
df["period"] = df["Year"] + df["quarter"]
If one (or both) of the columns are not string typed, you should convert it (them) first,
df["period"] = df["Year"].astype(str) + df["quarter"]
Beware...
Limits of Nat type in Shapeless
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Here is an example of a Concat type class that allows to concatenate two type-level strings via a macro. A type class for summing type-level integers would probably look very similar.
– Frank S. Thomas
Apr 16 '...
How can I get selector from jQuery object
...rn this.tagName; })
.get()
.reverse()
.concat([this.nodeName])
.join(">");
var id = $(this).attr("id");
if (id) {
selector += "#"+ id;
}
var classNames = $(this).attr("class");
if (cla...
How to run Gulp tasks sequentially one after the other
... you return a stream in task one, e.g. return gulp.src('app/**/*.js').pipe(concat(app.js)).pipe(gulp.dest('app/scripts');, the key is to identify task one as a dependent when defining task two: gulp.task('two', ['one'], function() {... Task two will now wait for task one to end before running.
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Concatenate strings in Less
...e it was changing my background-image url, and I wasn't too sure how to do concatenation :)
– hatsrumandcode
Dec 22 '15 at 16:18
7
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How do I replace a character at a particular index in JavaScript?
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You can't. Take the characters before and after the position and concat into a new string:
var s = "Hello world";
var index = 3;
s = s.substring(0, index) + 'x' + s.substring(index + 1);
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