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How to determine if a list of polygon points are in clockwise order?
...se. (The result is twice the enclosed area, with a +/- convention.)
point[0] = (5,0) edge[0]: (6-5)(4+0) = 4
point[1] = (6,4) edge[1]: (4-6)(5+4) = -18
point[2] = (4,5) edge[2]: (1-4)(5+5) = -30
point[3] = (1,5) edge[3]: (1-1)(0+5) = 0
point[4] = (1,0) edge[4]: (5-1)(0+0) = 0
...
Why isn't my Pandas 'apply' function referencing multiple columns working? [closed]
...[44]: df
Out[44]:
a b c Value
0 -1.674308 foo 0.343801 0.044698
1 -2.163236 bar -2.046438 -0.116798
2 -0.199115 foo -0.458050 -0.199115
3 0.918646 bar -0.007185 -0.001006
4 1.336830 foo 0.534292 0.268245
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Why are elementwise additions much faster in separate loops than in a combined loop?
...
10 Answers
10
Active
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How to make link look like a button?
...
107
Using CSS:
.button {
display: block;
width: 115px;
height: 25px;
backg...
.NET 4.0 has a new GAC, why?
...the new GAC . Does it mean now we have to manage two GACs, one for .NET 2.0-3.5 applications and the other for .NET 4.0 applications?
...
Android: How to change CheckBox size?
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answered Jan 28 '10 at 7:36
moraesmoraes
11.8k77 gold badges4141 silver badges5858 bronze badges
...
How do I check if there are duplicates in a flat list?
...
406
Use set() to remove duplicates if all values are hashable:
>>> your_list = ['one', 't...
Avoid trailing zeroes in printf()
...ormat specifiers. The closest you could get would be:
printf("%.6g", 359.013); // 359.013
printf("%.6g", 359.01); // 359.01
but the ".6" is the total numeric width so
printf("%.6g", 3.01357); // 3.01357
breaks it.
What you can do is to sprintf("%.20g") the number to a string buffer then man...
How can I convert a Unix timestamp to DateTime and vice versa?
...
1059
Here's what you need:
public static DateTime UnixTimeStampToDateTime( double unixTimeStamp )
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How To: Best way to draw table in console app (C#)
...ring text, int width)
{
text = text.Length > width ? text.Substring(0, width - 3) + "..." : text;
if (string.IsNullOrEmpty(text))
{
return new string(' ', width);
}
else
{
return text.PadRight(width - (width - text.Length) / 2).PadLeft(width);
}
}
...