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What is the purpose of using -pedantic in GCC/G++ compiler?
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GCC compilers always try to compile your program if this is at all possible. However, in some
cases, the C and C++ standards specify that certain extensions are forbidden. Conforming compilers
such as gcc or g++ must issue a diagnostic when these extensions are encountered. For example,
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How to set default value to the input[type=“date”] [duplicate]
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@sheriffderek . This is not supported in all browsers, you need a jquery or similar fallback solution
– jonah
May 3 '17 at 2:49
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Is Python strongly typed?
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Python is strongly, dynamically typed.
Strong typing means that the type of a value doesn't change in unexpected ways. A string containing only digits doesn't magically become a number, as may happen in Perl. Every change of type requires an explicit...
Node.js app can't run on port 80 even though there's no other process blocking the port
I'm running an instance of Debian on Amazon EC2 with Node.js installed. If I run the code below:
9 Answers
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How to call a stored procedure from Java and JPA
I am writing a simple web application to call a stored procedure and retrieve some data.
Its a very simple application, which interacts with client's database. We pass employee id and company id and the stored procedure will return employee details.
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How can I create an error 404 in PHP?
My .htaccess redirects all requests to /word_here to /page.php?name=word_here . The PHP script then checks if the requested page is in its array of pages.
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error LNK2019: unresolved external symbol _WinMain@16 referenced in function ___tmainCRTStartup
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This worked only after I selected "all configurations" for both platform and type. Selecting "build" on the "Solution" attempted to build all and the first one tried was NOT the one had specified for console subsystem.
– Joseph Stateson
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Can I implement an autonomous `self` member type in C++?
...question, not the answer. In many cases in software development (and especially maintenance) it is helpful to avoid redundancies in the code, so that changing something in one place does not require you to change code in another place. That's the whole point of auto and decltype or in this case of s...
Is Java “pass-by-reference” or “pass-by-value”?
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Java is always pass-by-value.
Unfortunately, we never handle an object at all, instead juggling object-handles called references (which are passed by value of course). The chosen terminology and semantics easily confuse many beginners.
It goes like this:
public static void main(String[] args) {
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fs: how do I locate a parent folder?
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why? just generally why? can someone please explain?
– eyurdakul
May 16 '17 at 15:12
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