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Detect Windows version in .net
... @LonnieBest - That is a method that determines whether it's x64 or x86... I didn't use that, just comment it out.
– Gabe
May 26 '10 at 13:53
2
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What does 'useLegacyV2RuntimeActivationPolicy' do in the .NET 4 config?
...ttribute.
http://www.marklio.com/marklio/PermaLink,guid,ecc34c3c-be44-4422-86b7-900900e451f9.aspx (Internet Archive Wayback Machine link)
To quote the most relevant bits:
[Installing .NET] v4 is “non-impactful”. It should not change the behavior of existing components when installed.
The useLe...
Why is JSHINT complaining that this is a strict violation?
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FlimmFlimm
86.4k2828 gold badges186186 silver badges191191 bronze badges
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unsigned int vs. size_t
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Nope. Think of x86-16 with the large (not huge) memory model: Pointers are far (32-bit), but individual objects are limited to 64k (so size_t can be 16-bit).
– dan04
Nov 28 '10 at 3:46
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How to display Base64 images in HTML?
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86
You need to specify correct Content-type, Content-encoding and charset
like
data:image/jpeg...
When should I use the “strictfp” keyword in java?
...oating point results to conform to the IEEE specification. In particular x86 processors can store intermediate results with different precision from the IEEE spec. The situation gets more complicated when the JIT optimizes a particular computation; the order the instructions could be different eac...
ASP.NET MVC Razor pass model to layout
...o some blog post that goes through this technique
– J86
Feb 20 '17 at 23:44
This can work but why take the performance...
What reason is there to use null instead of undefined in JavaScript?
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86
I don't really have an answer, but according to Nicholas C. Zakas, page 30 of his book "Profess...
How can I configure Logback to log different levels for a logger to different destinations?
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86
I believe this would be the simplest solution:
<configuration>
<contextName>se...
How do you get the magnitude of a vector in Numpy?
...))
In [3]: %timeit [np.linalg.norm(x) for x in a]
100 loops, best of 3: 3.86 ms per loop
In [4]: %timeit np.sqrt((a*a).sum(axis=1))
100000 loops, best of 3: 15.6 µs per loop
In [5]: %timeit np.sqrt(np.einsum('ij,ij->i',a,a))
100000 loops, best of 3: 8.71 µs per loop
or vectors:
In [5]: a ...