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How to disable scrolling temporarily?
...e scrolling is that when you scroll while scrollTo is animating, it gets really ugly ;)
35 Answers
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How to determine a Python variable's type?
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It is so simple. You do it like this.
print(type(variable_name))
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assertEquals vs. assertEqual in python
...as been deprecated as well:
Method Name | Deprecated alias(es)
_________________________________________________________
assertEqual() | failUnlessEqual, assertEquals
From 25.3.7.1.1. Deprecated aliases
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transform object to array with lodash
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You can do
var arr = _.values(obj);
For documentation see here.
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Forward declaring an enum in C++
...can't know the storage required for the enum variable. C++ Compiler's are allowed to specify the actual storage space based on the size necessary to contain all the values specified. If all that is visible is the forward declaration, the translation unit can't know what storage size will have been...
Python decorators in classes
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Would something like this do what you need?
class Test(object):
def _decorator(foo):
def magic( self ) :
print "start magic"
foo( self )
print "end magic"
return magic
@_decorator
def bar( self ) :
print "normal call"
test ...
Django FileField with upload_to determined at runtime
...eed to use the filename given - you could override that in your upload_to callable too if you liked.
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What is the difference between an interface and abstract class?
...'t do anything. It's just a pattern.
For example (pseudo code):
// I say all motor vehicles should look like this:
interface MotorVehicle
{
void run();
int getFuel();
}
// My team mate complies and writes vehicle looking that way
class Car implements MotorVehicle
{
int fuel;
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What is the use for Task.FromResult in C#
In C# and TPL ( Task Parallel Library ), the Task class represents an ongoing work that produces a value of type T.
6 Ans...
How to refer to relative paths of resources when working with a code repository
...Try to use a filename relative to the current files path. Example for './my_file':
fn = os.path.join(os.path.dirname(__file__), 'my_file')
In Python 3.4+ you can also use pathlib:
fn = pathlib.Path(__file__).parent / 'my_file'
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