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How to list out all the subviews in a uiviewcontroller in iOS?
...iews];
// Return if there are no subviews
if ([subviews count] == 0) return; // COUNT CHECK LINE
for (UIView *subview in subviews) {
// Do what you want to do with the subview
NSLog(@"%@", subview);
// List the subviews of subview
[self listSubviewsOfV...
Why should I use tags vs. release/beta branches for versioning?
...ow is why use tagging at all if I can just create a new branch called 1.1.0 and not have to cloud my mind with a whole new set of git commands?
...
rails simple_form - hidden field - create?
...
310
try this
= f.input :title, :as => :hidden, :input_html => { :value => "some value" }
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nginx missing sites-available directory
...|
edited Jun 26 '18 at 21:00
user2066657
27822 silver badges1414 bronze badges
answered Jul 2 '13 at 0:2...
How to prevent browser page caching in Rails
...nse.headers["Pragma"] = "no-cache"
response.headers["Expires"] = "Mon, 01 Jan 1990 00:00:00 GMT"
end
end
Rails 4 and older versions:
class ApplicationController < ActionController::Base
before_filter :set_cache_headers
private
def set_cache_headers
response.headers["Cache-Co...
How to remove element from array in forEach loop?
...'b', 'c', 'b', 'a', 'a'],
index = review.length - 1;
while (index >= 0) {
if (review[index] === 'a') {
review.splice(index, 1);
}
index -= 1;
}
log(review);
<pre id="out"></pre>
Ok, but you wanted to use ES5 iteration methods. Well and option would be to use Arra...
rspec 3 - stub a class method
I am upgrading from rspec 2.99 to rspec 3.0.3 and have converted instance methods to use allow_any_instance_of , but haven't figured out how to stub a class method. I have code like this:
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Using .sort with PyMongo
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207
sort should be a list of key-direction pairs, that is
db.test.find({"number": {"$gt": 1}}).sor...
How to attach debugger to iOS app after launch?
...evice.
– James Moore
Feb 25 '14 at 20:24
4
NOTE: In Xcode 5.0.1+ it is Debug > Attach to Proce...
Escape regex special characters in a Python string
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203
Use re.escape
>>> import re
>>> re.escape(r'\ a.*$')
'\\\\\\ a\\.\\*\\$'
>...