大约有 43,870 项符合查询结果（耗时：0.0297秒） [XML]
Converting a list to a set changes element order
...the list, you can do this with a list comprehension:
>>> a = [1, 2, 20, 6, 210]
>>> b = set([6, 20, 1])
>>> [x for x in a if x not in b]
[2, 210]
If you need a data structure that supports both fast membership tests and preservation of insertion order, you can use the k...
Shuffle two list at once with same order
...t pre-processing. But there is problem, in lists documents and documents2 I have the same documents and I need shuffle them in order to keep same order in both lists. I cannot shuffle them separately because each time I shuffle the list, I get other results. That is why I need to shuffle the at ...
Transpose/Unzip Function (inverse of zip)?
I have a list of 2-item tuples and I'd like to convert them to 2 lists where the first contains the first item in each tuple and the second list holds the second item.
...
Finding the index of elements based on a condition using python list comprehension
...t all, but just deal with the values—[value for value in a if value > 2]. Usually dealing with indexes means you're not doing something the best way.
If you do need an API similar to Matlab's, you would use numpy, a package for multidimensional arrays and numerical math in Python which is heavi...
2024 全“心”出发 -- 全新App Inventor 2 移动社区开启新征程 - App Inven...
全新的App Inventor 2 移动技术社区全面改版，全新上线，邀您体验！
感谢您对我们的支持！正是因为您的支持和信任，我们才能不断前行，不断改进。我们承诺，无论是技术问题还是社区建设，我们始终保持诚恳、负责的态度，...
App Inventor 2 实现导出Excel全方案总结 · App Inventor 2 中文网
... 教育 入门必读 中文教程 IoT专题 AI2拓展 ChatGPT接入 Aia Store 开通VIP 搜索 App Inventor 2 实现导出Excel全方案总结...
App Inventor 2 天气预报App开发 - 第三方API接入的通用方法 · App Inventor 2 中文网
... 教育 入门必读 中文教程 IoT专题 AI2拓展 ChatGPT接入 Aia Store 开通VIP 搜索
App Inventor 2 天气预报App开发 - 第三...
Regex to match a digit two or four times
...
2 Answers
2
Active
...
How do I compare two hashes?
...can compare hashes directly for equality:
hash1 = {'a' => 1, 'b' => 2}
hash2 = {'a' => 1, 'b' => 2}
hash3 = {'a' => 1, 'b' => 2, 'c' => 3}
hash1 == hash2 # => true
hash1 == hash3 # => false
hash1.to_a == hash2.to_a # => true
hash1.to_a == hash3.to_a # => false
...
Remove all values within one list from another list? [duplicate]
...
>>> a = range(1, 10)
>>> [x for x in a if x not in [2, 3, 7]]
[1, 4, 5, 6, 8, 9]
share
|
improve this answer
|
follow
|
...