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Installing Numpy on 64bit Windows 7 with Python 2.7.3 [closed]
...nstaller for Numpy is for Numpy version 1.3.0 which only works with Python 2.6
6 Answers
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How many double numbers are there between 0.0 and 1.0?
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Java doubles are in IEEE-754 format, therefore they have a 52-bit fraction; between any two adjacent powers of two (inclusive of one and exclusive of the next one), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that's the...
How to check if all elements of a list matches a condition?
I have a list consisting of like 20000 lists. I use each list's 3rd element as a flag. I want to do some operations on this list as long as at least one element's flag is 0, it's like:
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Round to at most 2 decimal places (only if necessary)
I'd like to round at most 2 decimal places, but only if necessary .
79 Answers
79
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What's the best practice to round a float to 2 decimals? [duplicate]
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I was working with statistics in Java 2 years ago and I still got the codes of a function that allows you to round a number to the number of decimals that you want. Now you need two, but maybe you would like to try with 3 to compare results, and this function giv...
Rspec: “array.should == another_array” but without concern for order
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265
Try array.should =~ another_array
The best documentation on this I can find is the code itsel...
counting number of directories in a specific directory
...* -maxdepth 0 -type d | wc -l
11
$ find .vim/ -maxdepth 1 -type d | wc -l
12
You can also use ls:
$ ls -l .vim | grep -c ^d
11
$ ls -l .vim
total 52
drwxrwxr-x 3 anossovp anossovp 4096 Aug 29 2012 after
drwxrwxr-x 2 anossovp anossovp 4096 Aug 29 2012 autoload
drwxrwxr-x 13 anossovp anossovp...
How to filter object array based on attributes?
...p;&
el.sqft >= 500 &&
el.num_of_beds >=2 &&
el.num_of_baths >= 2.5;
});
Live Example:
var obj = {
'homes': [{
"home_id": "1",
"price": "925",
"sqft": "1100",
"num_of_beds": "2",
...
Boolean operators && and ||
...rter ones are vectorized, meaning they can return a vector, like this:
((-2:2) >= 0) & ((-2:2) <= 0)
# [1] FALSE FALSE TRUE FALSE FALSE
The longer form evaluates left to right examining only the first element of each vector, so the above gives
((-2:2) >= 0) && ((-2:2) <...