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How to use java.String.format in Scala?
I am trying to use a .format method of a string. But if I place %1, %2, etc. in the string, java.util.UnknownFormatConversionException is thrown pointing to a confusing Java source code piece:
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How to keep Maven profiles which are activeByDefault active even if another profile gets activated?
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One trick is to avoid activeByDefault, and instead activate the profile by the absence of a pr...
What is the PostgreSQL equivalent for ISNULL()
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edited Jan 14 '12 at 2:28
Erwin Brandstetter
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How to convert URL parameters to a JavaScript object?
... the answer based on the comments.
var search = location.search.substring(1);
JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
Example
Parse abc=foo&def=%5Basf%5D&xyz=5 in five steps:
decodeURI: abc=foo&def=[asf]&xyz=...
MySQL - SELECT WHERE field IN (subquery) - Extremely slow why?
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10 Answers
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How to verify a method is called two times with mockito verify()
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1 Answer
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How to remove the querystring and get only the url?
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16 Answers
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Error while pull from git - insufficient permission for adding an object to repository database .git
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edited Dec 15 '16 at 23:25
answered Nov 5 '13 at 23:20
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Programmatically retrieve memory usage on iPhone
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To get the actual bytes of memory that your application is using, you can do something like th...