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Read String line by line

Given a string that isn't too long, what is the best way to read it line by line? 11 Answers ...
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How to check if a string starts with a specified string? [duplicate]

I'm trying to check if a string starts with http . How can I do this check? 6 Answers ...
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String variable interpolation Java [duplicate]

String building in Java confounds me. I abhore doing things like: 5 Answers 5 ...
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UILabel with text of two different colors

I want to display a string like this in a UILabel : 20 Answers 20 ...
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Java: convert List to a String

...this without any third party library. If you want to join a Collection of Strings you can use the new String.join() method: List<String> list = Arrays.asList("foo", "bar", "baz"); String joined = String.join(" and ", list); // "foo and bar and baz" If you have a Collection with another typ...
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C# Sanitize File Name

... To clean up a file name you could do this private static string MakeValidFileName( string name ) { string invalidChars = System.Text.RegularExpressions.Regex.Escape( new string( System.IO.Path.GetInvalidFileNameChars() ) ); string invalidRegStr = string.Format( @"([{0}]*\.+$)...
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Using AES encryption in C#

...tatic void Main() { try { string original = "Here is some data to encrypt!"; // Create a new instance of the RijndaelManaged // class. This generates a new key and initialization // vector (IV). ...
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get dictionary value by key

... It's as simple as this: String xmlfile = Data_Array["XML_File"]; Note that if the dictionary doesn't have a key that equals "XML_File", that code will throw an exception. If you want to check first, you can use TryGetValue like this: string xmlfi...
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How do I convert a TimeSpan to a formatted string? [duplicate]

... Would TimeSpan.ToString() do the trick for you? If not, it looks like the code sample on that page describes how to do custom formatting of a TimeSpan object. share ...
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Type safety: Unchecked cast

...vailable to the garbage collector. So, don't do that, use: private Map<String, String> someMap = (HashMap<String, String>)getApplicationContext().getBean("someMap"); Secondly, the compiler is complaining that you cast the object to a HashMap without checking if it is a HashMap. But, e...