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Pass variables to Ruby script via command line
...uts "Argument: #{a}"
end
then
$ ./test.rb "test1 test2"
or
v1 = ARGV[0]
v2 = ARGV[1]
puts v1 #prints test1
puts v2 #prints test2
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Break out of a While…Wend loop
...o a Do loop instead:
Do While True
count = count + 1
If count = 10 Then
Exit Do
End If
Loop
Or for looping a set number of times:
for count = 1 to 10
msgbox count
next
(Exit For can be used above to exit prematurely)
...
Getting exact error type in from DbValidationException
...iest way I've found to get instant insight into these errors.
For Visual 2012+ users who care only about the first error and might not have a catch block, you can even do:
((System.Data.Entity.Validation.DbEntityValidationException)$exception).EntityValidationErrors.First().ValidationErrors.First(...
Checking oracle sid and database name
...
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edited Feb 20 at 6:39
Stefan van den Akker
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Does async(launch::async) in C++11 make thread pools obsolete for avoiding expensive thread creation
...verhead for creating a thread to handle a function call is something like 10000 or more times slower than a plain function call. So, if you're issuing a lot of small function calls, a thread pool might be a good idea.
It's quite apparent that the standard C++ library that ships with g++ doesn't hav...
Use of undeclared identifier 'kUTTypeMovie'
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The dudeThe dude
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1
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How to compare two files not in repo using git
...> y
$ git diff --color-words --no-index x y
diff --git a/x b/y
index 6b10c7c..70f036c 100644
--- a/x
+++ a/y
@@ -1 + 1 @@
Wed Jun 10 10:57:45|10:57:47 EDT 2013
The color can't be shown here so I separated the changes with a pipe in the example.
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How do I list loaded plugins in Vim?
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edited Mar 2 '16 at 14:10
Sicco
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answered Sep 8...
Groovy / grails how to determine a data type?
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edited Apr 22 '10 at 8:24
answered Jan 13 '10 at 21:34
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Swapping two variable value without using third variable
...mory locations (rather than different values). This is because (p xor p) = 0 and if both x and y share the same memory location, when one is set to 0, both are set to 0.
When both *x and *y are 0, all other xor operations on *x and *y will equal 0 (as they are the same), which means that the functio...