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Path of assets in CSS files in Symfony 2

I have a CSS file with some paths in it (for images, fonts, etc.. url(..) ). 6 Answers ...
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Git: cannot checkout branch - error: pathspec '…' did not match any file(s) known to git

...o checkout new branch: error: pathspec 'BRANCH-NAME' did not match any file(s) known to git. When I tried git checkout origin/<BRANCH-NAME>, I got the detached HEAD: (detached from origin/) Finally, I did the following to resolve the issue: git remote update git fetch git checko...
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Remote debugging a Java application

... You need to know the source code. Either you have the .java files or you have the .jar / .class files combined with the decompiler. IDE such as Eclipse can have a decompiler such as JDecompiler installed so that you can debug the .class file as if it's a .java file (excluding the comm...
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I didn't find “ZipFile” class in the “System.IO.Compression” namespace

I can't use "Zipfile" class in the name space "System.IO.Compression" my code is : 10 Answers ...
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Can I control the location of .NET user settings to avoid losing settings on application upgrade?

I'm trying to customize the location of the user.config file. Currently it's stored with a hash and version number 4 Ans...
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How to give Jenkins more heap space when it´s started as a service under Windows?

... As of Ubuntu 16.04.6 LTS, there's no such file. The /etc/default/jenkins solution offered below by Steve is the one that works for me. – insideClaw Jan 24 at 11:14 ...
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How to leave/exit/deactivate a Python virtualenv

... deactivate is a function that gets created when you source the activate file. Your suggestion to do source deactivate doesn't make sense at all, as there is no file named deactivate – Anthon Apr 12 '15 at 8:14 ...
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Read url to string in few lines of java code

... One line of code, and tens of megabytes of extraneous class files that are now in your runtime. Including a gigantic library to avoid writing a few (actually, one) line of code is not a great decision. – Jeffrey Blattman Nov 22 '17 at 1:19 ...
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How to get body of a POST in php?

...y body of a POST or PUT request (or any other HTTP method): $entityBody = file_get_contents('php://input'); Also, the STDIN constant is an already-open stream to php://input, so you can alternatively do: $entityBody = stream_get_contents(STDIN); From the PHP manual entry on I/O streamsdocs: ...
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Execute SQLite script

...n.db < create.sql SQLite's version of SQL doesn't understand < for files, your shell does. share | improve this answer | follow | ...