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How do I check if a number evaluates to infinity?
...ine but it won't be so obvious to maintainers of your code what you're actually trying to test for. I agree that using isFinite is almost always the better way to do things -- that's why I mentioned it in my answer -- but only the OP can decide whether it meets their requirements.
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How to make my custom type to work with “range-based for loops”?
...hanges, and compilers that do not.
The objects returned do not have to actually be iterators. The for(:) loop, unlike most parts of the C++ standard, is specified to expand to something equivalent to:
for( range_declaration : range_expression )
becomes:
{
auto && __range = range_expressi...
Sleep until a specific time/date
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Thanks for that, I wrote a small shell-script to get a "sleepuntil" command.
– theomega
Mar 14 '09 at 15:20
1
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Multiprocessing - Pipe vs Queue
... as a bonus; JoinableQueue() accounts for tasks when queue.task_done() is called (it doesn't even know about the specific task, it just counts unfinished tasks in the queue), so that queue.join() knows the work is finished.
The code for each at bottom of this answer...
mpenning@mpenning-T61:~$ pyt...
printf format specifiers for uint32_t and size_t
...ng size_t to be the same as unsigned long (possibly 64 bits) when it's actually an unsigned int (32 bits). Try using %zu in both cases.
I'm not entirely certain though.
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Python Unicode Encode Error
...80\x80abcd\xde\xb4'
>>> u.encode('ascii')
Traceback (most recent call last):
File "<stdin>", line 1, in ?
UnicodeEncodeError: 'ascii' codec can't encode character '\ua000' in position 0: ordinal not in range(128)
>>> u.encode('ascii', 'ignore')
'abcd'
>>> u.encode(...
Where do “pure virtual function call” crashes come from?
...programs that crash on my computer with the error: "pure virtual function call".
8 Answers
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Circular list iterator in Python
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Output:
a b c a b c ...
(Loops forever, obviously)
In order to manually advance the iterator and pull values from it one by one, simply call next(pool):
>>> next(pool)
'a'
>>> next(pool)
'b'
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How do I know if a generator is empty from the start?
..., there is no simple way. There are a whole lot of work-arounds.
There really shouldn't be a simple way, because of what generators are: a way to output a sequence of values without holding the sequence in memory. So there's no backward traversal.
You could write a has_next function or maybe eve...
Ruby replace string with captured regex pattern
...d answer first without reading the entirety of answers. That seems to generally be the most efficient means of fixing a problem. Give Vicky a break! :)
– Josh M.
Jan 31 '14 at 3:43
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