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How to get record created today by rails activerecord?
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123
I know this question has an accepted answer. The solution suggested in the accepted answer can...
How do I work around JavaScript's parseInt octal behavior?
... Number needs quotes around the 08. Also just be warned, Number('08.123') will produce 8.123 as its output. If you really want an integer, don't use Number (or pattern-match your input to ensure integers only).
– Jason S
May 11 '09 at 22:22
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Install a Windows service using a Windows command prompt?
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If the directory's name has a space like c:\program files\abc 123, then you must use double quotes around the path.
installutil.exe "c:\program files\abc 123\myservice.exe"
It makes things much easier if you set up a bat file like following,
e.g. To install a service, create a "my...
Difference between Node object and Element object?
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What about <span data-a="1" >123</span> ? this span is an element which has it's own node. but does the attribute also has it's own node ?
– Royi Namir
Mar 25 '14 at 9:44
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Press alt + numeric in bash and you get (arg [numeric]) what is that?
... + numeric and then you press a character, you'll get num caracters: (arg: 123) + a -> 123 times "a"
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Converting A String To Hexadecimal In Java
I am trying to convert a string like "testing123" into hexadecimal form in java. I am currently using BlueJ.
21 Answers
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Pretty-Print JSON in Java
...1111") // "number":"555-1111",
.write("extension", "123") // "extension":"123"
.writeEnd() // },
.writeStartObject() // {
.write("number", "555-2222") // "number":"555-2222",
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Ordering by the order of values in a SQL IN() clause
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Two solutions that spring to mind:
order by case id when 123 then 1 when 456 then 2 else null end asc
order by instr(','||id||',',',123,456,') asc
(instr() is from Oracle; maybe you have locate() or charindex() or something like that)
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How can building a heap be O(n) time complexity?
...d you mean to start at the bottom of the heap?
– aste123
Dec 16 '15 at 18:14
4
@aste123 No, it is...
Check if multiple strings exist in another string
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You need to iterate on the elements of a.
a = ['a', 'b', 'c']
str = "a123"
found_a_string = False
for item in a:
if item in str:
found_a_string = True
if found_a_string:
print "found a match"
else:
print "no match found"
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